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sin^21·+sin^22·+sin^23·+……+sin^289·=?(·为度)

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解决时间 2021-03-11 22:34
  • 提问者网友:皆是孤独
  • 2021-03-11 08:56
sin^21·+sin^22·+sin^23·+……+sin^289·=?(·为度)
最佳答案
  • 五星知识达人网友:蓝房子
  • 2021-03-11 09:55
sin^21·+sin^22·+sin^23·+……+sin^289·
=1/2 (sin^21·+sin^22·+sin^23·+……+sin^289·+sin^21·+sin^22·+sin^23·+……+sin^289·)

=1/2 【(sin^21·++sin^289)·(sin^22·+88°)+(sin^23·+87°)+……+(sin^289·+sin^21)】
=1/2 [1+1+...+1]
=1/2×89
=44.5
全部回答
  • 1楼网友:逃夭
  • 2021-03-11 11:33
sin^21·+sin^22·+sin^23·+……+sin^289· =0.5[(sin^21·+sin^22·+sin^23·+……+sin^289 ) + (sin^289·+sin^288·+sin^287·+……+sin^21·)] =0.5*89 =44.5
  • 2楼网友:北方的南先生
  • 2021-03-11 10:23
sin^21·+sin^22·+sin^23·+……+sin^289· =1/2 (sin^21·+sin^22·+sin^23·+……+sin^289·+sin^21·+sin^22·+sin^23·+……+sin^289·) =1/2 【(sin^21·++sin^289)·(sin^22·+88°)+(sin^23·+87°)+……+(sin^289·+sin^21)】 =1/2 [1+1+...+1] =1/2×89 =44.5O(∩_∩)O谢谢
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