把一个16进制数转换成一个10进制数。

vb作业，谢谢~~~~~~~~~

Function hex2dec(h As String) As Long
Dim n As Long, t As String
For i = 1 To Len(h)
t = UCase(Mid(h, Len(h) - i + 1, 1))
If t > "A" Then
n = n * 16 + 10 + Asc(t) - Asc("A")
Else
n = n * 16 + Asc(t) - Asc("0")
End If
Next i
hex2dec = n
End Function

Private Sub Command1_Click()
Print hex2dec("ffff")
End Sub

Private Sub Command1_Click() Text2.Text = "" ST Text1.Text End Sub Private Sub ST(strz As String) Dim s As Integer, a As Integer, i As Integer, strg As String 'strz是你输入的16进制数 For i = Len(strz) To 1 Step -1 strg = Mid(strz, i, 1) If Asc(strg) >= 65 And Asc(strg) <= 70 Then a = Asc(strg) - 55 ElseIf Asc(strg) >= 97 Then a = Asc(strg) - 87 Else a = strg End If s = s + a * 16 ^ (i - 1) Next i Text2 = Text2 & s End Sub Private Sub Text1_KeyPress(KeyAscii As Integer) If (KeyAscii < 65 Or KeyAscii > 70) And (KeyAscii < 97 Or KeyAscii > 102) And (KeyAscii < 48 Or KeyAscii > 57) Then i = MsgBox("请输入16进制数") End If End Sub

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