构造十六进制转换十进制函数,求大神解答疑惑,在线等,无比感激~~

Write a function that parses a hex number as a string into a decimal integer.
The function header is as follows:
int parseHex(const char * const hexString)
For example, hexString "A5" is 165 (10*16+5=165). So, parseHex("A5") returns 165.
上面是题目的要求,下面是我的码
#include
#include
int parseHex(const char * const hexString){
int result;
int len = strlen(hexString);
for(int i=0;iint dec = 0;
if(hexString[i]>='0'&&hexString[i]<='9') dec=hexString[i]-'0';
else if(hexString[i]>='A'&&hexString[i]<='F') dec=hexString[i]-'A'+10;
else if(hexString[i]>='a'&&hexString[i]<='f') dec=hexString[i]-'a'+10;
result=result+dec*pow(16,len-i-1);
}
return result;
为什么测了几组数据都对,提交还是WA呢?

改成这样试试：
int parseHex(const char * const hexString){
int result=0; //...
int len = strlen(hexString);
int dec = 0;
for(int i=0; i if(hexString[i]>='0' && hexString[i]<='9') dec=hexString[i]-'0';
else if(hexString[i]>='A' && hexString[i]<='F') dec=hexString[i]-'A'+10;
else if(hexString[i]>='a' && hexString[i]<='f') dec=hexString[i]-'a'+10;
result=16*result+dec; //...
}
return result;
}

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