初一数学题.做对的悬赏100分因式分解:16(a-b)²-9(a+b)².(x+
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解决时间 2021-02-24 23:39
- 提问者网友:暗中人
- 2021-02-24 06:10
初一数学题.做对的悬赏100分因式分解:16(a-b)²-9(a+b)².(x+
最佳答案
- 五星知识达人网友:几近狂妄
- 2021-02-24 06:40
16(a-b)²-9(a+b)²={4(a-b)}²-{3(a+b)}²={4(a-b)+3(a+b)}x{4(a-b)-3(a+b)}=(7a-b)(a-7b) (x+y)(m+n)²-(x+y)(m-n)²=(x+y)[(m+n)²-(m-n)²]=(x+y)[(m+n+m-n)(m+n-m+n)](x²+y²)²-4x²y²=(x²+y²)²-(2xy)²=(x²+y²+2xy)(x²+y²-2xy)=(x+y)²(x-y)²======以下答案可供参考======供参考答案1:16(a-b)²-9(a+b)²=(4a-4b)²-(3a+3b)²=(4a-4a+3a+3b)(4a-4b-3a-3b)(x+y)(m+n)²-(x+y)(m-n)²=(x+y)[(m+n)²-(m-n)²]=(x+y)[(m+n+m-n)(m+n-m+n)]=(x²+y²)²-(2xy)²=(x²+y²+2xy)(x²+y²-2xy)=(x+y)²(x-y)²供参考答案2:16(a-b)²-9(a+b)²=(4a-4b)²-(3a+3b)²=(4a-4a+3a+3b)(4a-4b-3a-3b)(x+y)(m+n)²-(x+y)(m-n)²=(x+y)[(m+n)²-(m-n)²]=(x+y)[(m+n+m-n)(m+n-m+n)](x²+y²)²-4x²y²=(x²+y²)²-(2xy)²=(x²+y²+2xy)(x²+y²-2xy)=(x+y)²(x-y)²
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- 1楼网友:几近狂妄
- 2021-02-24 07:11
谢谢回答!!!
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