﹙2a+1／a²-1﹚·﹙a²-2a+1／a²-a﹚﹣﹙1／a+1﹚其中a=1／2 先化简再求值
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解决时间 2021-12-30 16:14
- 提问者网友：無理詩人
- 2021-12-30 06:02
﹙2a+1／a²-1﹚·﹙a²-2a+1／a²-a﹚﹣﹙1／a+1﹚其中a=1／2 先化简再求值
最佳答案
- 五星知识达人网友：怀裏藏嬌
- 2021-12-30 06:46
2a+1／a²a(a+1)
= a+1/a(a+1) - a/a(a-1) - ﹙1／a+1﹚
= 2a+1/a(a+1) - ﹙1／a+1﹚
= 2a+1/-2a+1／a²-a﹚﹣﹙1／a+1﹚
= 2a+1/(a+1)(a-1) - (a-1)²/-1﹚·﹙a²a(a+1)
= 1/
= a+1/a(a+1) - a/a(a-1) - ﹙1／a+1﹚
= 2a+1/a(a+1) - ﹙1／a+1﹚
= 2a+1/-2a+1／a²-a﹚﹣﹙1／a+1﹚
= 2a+1/(a+1)(a-1) - (a-1)²/-1﹚·﹙a²a(a+1)
= 1/
全部回答
- 1楼网友：渊鱼
- 2021-12-30 08:04
[(a²-2a+1)/(a²-1)+(a²-a)/(a+1)+2]/a
=[(a-1)/(a+1)+(a²-a)/(a+1)+2]/a
=(a-1+2)/a
=(a+1)/a
=1+1/a；把a=√3代入
=1+√3/3
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