(1-y)/3 - 2y = 3 - (y+2)/4
求Y是多少 ?
(1-y)/3 - 2y = 3 - (y+2)/4
求Y是多少 ?
(1-y)/3 - 2y = 3 - (y+2)/4
解:两边乘以12得 4-4y-24y=36-3y-6
解得y=-26/ 25
两边 同时乘以12 得
4(1-y)-24y=36-3(y+2) 化简得25y=-26 y= - 26/25
1/3-1/3y-2y=3-1/4y-1/2
y=-26/25
望采纳
(1-y)/3 - 2y = 3 - (y+2)/4
4(1-y)-24y=36-3(y+2)
4-4y-24y=36-3y-6
25y=-26
y=-26/25