1/x+1十1/x+4=1/x+2十1/x+3
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解决时间 2021-04-02 06:12
- 提问者网友:且恨且铭记
- 2021-04-01 10:51
1/x+1十1/x+4=1/x+2十1/x+3
最佳答案
- 五星知识达人网友:上分大魔王
- 2021-04-01 11:02
1/(x+1)+1/(x+4)=1/(x+2)+1/(x+3)
1/(x+1) -1/(x+2) = 1/(x+3)- 1/(x+4)
1/[(x+1)(x+2)] = 1/[(x+3)(x+4)]
(x+1)(x+2) =(x+3)(x+4)
x^2+3x+2 = x^2+7x+12
4x=-10
x=-5/2
1/(x+1) -1/(x+2) = 1/(x+3)- 1/(x+4)
1/[(x+1)(x+2)] = 1/[(x+3)(x+4)]
(x+1)(x+2) =(x+3)(x+4)
x^2+3x+2 = x^2+7x+12
4x=-10
x=-5/2
全部回答
- 1楼网友:封刀令
- 2021-04-01 12:36
1/x+1十1/x+4=1/x+2十1/x+3
1/(x+1)-1/(x+2)=1/(x+3)-1/(x+4)
1/(x²+3x+2)=1/(x²+7x+12)
x²+7x+12=x²+3x+2
4x=-10
x=-2.5
1/(x+1)-1/(x+2)=1/(x+3)-1/(x+4)
1/(x²+3x+2)=1/(x²+7x+12)
x²+7x+12=x²+3x+2
4x=-10
x=-2.5
- 2楼网友:思契十里
- 2021-04-01 11:37
(x+1+x+4)/(x²+5x+4)=(x+2+x+3)/(x²+5x+6)
2x+5=0
x=-5/2
2x+5=0
x=-5/2
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