VB.NET中怎么调用ReadProcessMemory？

答案:2 悬赏:20 手机版

解决时间 2021-04-09 12:44

提问者网友：临风不自傲
2021-04-08 16:41

请举例说明~重点说明下第3个参数！

为什么在buffer那里显示“类型BYTE的1维数组的值无法转换成Integer”
并且用buffer.Length时候显示错误不是SYSTEM.LENTH中的方法

最佳答案

五星知识达人网友：罪歌
2021-04-08 17:37

以前有人问过，给你说一下:
声明
Public Declare Function ReadProcessMemory Lib "kernel32" (ByVal hProcess As Integer, ByVal lpBaseAddress As Integer, ByVal lpBuffer() As Byte, ByVal nSize As Integer, ByRef lpNumberOfBytesWritten As Integer) As Integer

示例:
Private Const PROCESS_VM_READ As Long = &H10
Sub Main()
Dim ph As Integer
Dim i As Integer
Dim h As Integer
Dim buffer(20) As Byte
Dim bytesRead As Integer
'获得进程
ph = OpenProcess(PROCESS_ALL_ACCESS, False, 1832)
If ph Then
MsgBox.Show("true")
h = ReadProcessMemory(ph, &H403000, buffer, buffer.Length, bytesRead)
For i = 0 To buffer.Length - 1
TempMem =TempMem+buffer(i).ToString
Next
Else
MsgBox.Show("false")
End If
end sub

全部回答

1楼网友：底特律间谍
2021-04-08 18:32

_ public shared function readprocessmemory(byval hprocess as intptr, _ byval lpbaseaddress as intptr, _ byval lpbuffer() as byte, _ byval dwsize as integer, _ byref lpbytesread as integer) as boolean end functiondim buffer(3) as byte() readprocessmemory(hprocess, &h274a024, buffer, buffer.length, bytesread)如果要读不到，用逐步调试看看hprocess有没有问题，还要检查&h274a024是否存在。

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