求数组中[hige]+ [bad]=$sum 的方法
Array
(
[0] => Array
(
[id] => 6
[path] => 160522/574162a4e1aad.mp4
[hige] => 20
[bad] => 10
[del] => 0
)
[1] => Array
(
[id] => 10
[path] => 160526/574697eed85f4.mp4
[hige] => 30
[bad] => 20
[del] => 0
)
)
求PHP多维数组相加
答案:1 悬赏:50 手机版
解决时间 2021-03-07 00:25
- 提问者网友:夢醒日落
- 2021-03-06 06:48
最佳答案
- 五星知识达人网友:平生事
- 2021-03-06 07:31
1.思路:
遍历、再遍历 即可实现;
2.代码如下:
<?php
$arr = array(
0 => array('id' => 6,'hige' => 20,'bad' => 10,'del' => 0),
1 => array('id' => 10,'hige' => 30,'bad' => 20,'del' => 0)
);
$i = 0;
foreach($arr as $k1=>$v1)
{
foreach($v1 as $k2 = >$v2)
{
if($k2 == 'hige' || $k2 == 'bad')
{
$i += $v2;
}
}
}
dump($i);
//int(80)
//$i即为数组里:键为hige和bad所对应的值的总和;
?>
遍历、再遍历 即可实现;
2.代码如下:
<?php
$arr = array(
0 => array('id' => 6,'hige' => 20,'bad' => 10,'del' => 0),
1 => array('id' => 10,'hige' => 30,'bad' => 20,'del' => 0)
);
$i = 0;
foreach($arr as $k1=>$v1)
{
foreach($v1 as $k2 = >$v2)
{
if($k2 == 'hige' || $k2 == 'bad')
{
$i += $v2;
}
}
}
dump($i);
//int(80)
//$i即为数组里:键为hige和bad所对应的值的总和;
?>
我要举报
如以上回答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息,可以点下面链接进行举报!
点此我要举报以上问答信息
大家都在看
推荐资讯