求极限lim(x→0)[tan3x/x]
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解决时间 2021-11-24 06:01
- 提问者网友：佞臣
- 2021-11-23 17:36
求极限lim(x→0)[tan3x/x]
最佳答案
- 五星知识达人网友：末日狂欢
- 2021-11-23 18:33
lim(x→0)[tan3x/x]
=lim(x→0)3[tan3x/3x]
=3
lim(x→1) (x²-2x+1)/(x²-1)
=lim(x→1) (x-1)²/[(x+1)(x-1)]
=lim(x→1) (x-1)/(x+1)
=0
希望对你有帮助，望采纳，谢谢~
=lim(x→0)3[tan3x/3x]
=3
lim(x→1) (x²-2x+1)/(x²-1)
=lim(x→1) (x-1)²/[(x+1)(x-1)]
=lim(x→1) (x-1)/(x+1)
=0
希望对你有帮助，望采纳，谢谢~
全部回答
- 1楼网友：几近狂妄
- 2021-11-23 19:17
lim(x→0)[tan3x/x]=3 lim(3x→0)[tan3x/3x]=3 lim(x→0)[sin3x/3x]lim(x→0)[1/cos3x]=3
lim(x→1)(x^2-2x+1)/(x^2-1)=lim(x→1)(x-1)^2/(x+1)(x-1)=lim(x→1)(x-1)/(x+1)=0
lim(x→1)(x^2-2x+1)/(x^2-1)=lim(x→1)(x-1)^2/(x+1)(x-1)=lim(x→1)(x-1)/(x+1)=0
- 2楼网友：逃夭
- 2021-11-23 18:44
lim(x→0)[tan3x/x]
=lim(x→0)[3x/x]
=3
(1)lim(x---->1)(x-1)/(x+1)
=0/2
=0
=lim(x→0)[3x/x]
=3
(1)lim(x---->1)(x-1)/(x+1)
=0/2
=0
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