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已知道1900年1月1日是星期一,请输入一具体的日期,如何判断此日期是星期几?请利用C语言来进行编程

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解决时间 2021-03-02 02:11
  • 提问者网友:趣果有间
  • 2021-03-01 16:51
各位大虾帮帮忙了~~~~~

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最佳答案
  • 五星知识达人网友:零点过十分
  • 2021-03-01 17:18
我的思路 先计算输入的日期与1900.1.1相差的天数 然后对7求余
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  • 1楼网友:空山清雨
  • 2021-03-01 18:28
这个是1984年1月1日是星期日的,你先看看,我再帮你改,最好自己能看懂 #include void main() { int year,month,day; int tempmonth,yearday; int week,weekday; unsigned int sum=0; int tag=0; printf("输入年、月、日:\n"); scanf("%d %d %d",&year,&month,&day); tag =( year - 1980 )/4; sum=(year-1984)*365 + tag; tempmonth = month - 1; yearday = 0; switch(tempmonth) { case 12:yearday+=31; case 11:yearday+=30; case 10:yearday+=31; case 9:yearday+=30; case 8:yearday+=31; case 7:yearday+=31; case 6:yearday+=30; case 5:yearday+=31; case 4:yearday+=30; case 3:yearday+=31; case 2:yearday+=28; case 1:yearday+=31; } yearday = yearday+day; if ((year-1984)%4==0 && month > 2) { yearday+=1; } sum=sum+yearday; if (year==1984) { sum-=1; } printf("距1984年1月1日一共有%d天\n",sum); weekday = (sum-1) % 7; week = yearday / 7; printf("今天是第%d个星期,星期%d",week,weekday); return ; } 下面是修改好的,能多给些分嘛?写程序不容易,还有,好好学习,这些不难,就是多花点时间而已 #include void main() { int year,month,day; int tempmonth,yearday; int week,weekday; int sum=0; int tag=0; printf("输入年、月、日:\n"); scanf("%d %d %d",&year,&month,&day); tag =( year - 1988 )/4; printf("tag=%d\n",tag); sum=(year-1990)*365 + tag; tempmonth = month - 1; yearday = 0; switch(tempmonth) { case 12:yearday+=31; case 11:yearday+=30; case 10:yearday+=31; case 9:yearday+=30; case 8:yearday+=31; case 7:yearday+=31; case 6:yearday+=30; case 5:yearday+=31; case 4:yearday+=30; case 3:yearday+=31; case 2:yearday+=28; case 1:yearday+=31; } yearday = yearday+day; if ((year-1988)%4==0 && month > 2) { yearday+=1; } sum=sum+yearday; printf("sum=%d\n",sum); printf("距1990年1月1日一共有%d天\n",sum); weekday = (sum-1) % 7+1; week = yearday / 7; printf("今天是第%d个星期,星期%d",week,weekday); return ; }
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