y=2cos(3x-π/3)的单调区间？

y=2cos(3x-π/3)的单调区间怎么求？

减区间

0+2kπ ≤ 3x-π/3 ≤ π+2kπ (k∈Z)

即

π/3 +2kπ ≤ 3x ≤ π+π/3+2kπ (k∈Z)

π/9 +2kπ/3 ≤ x ≤ π/3+π/9+2kπ/3 (k∈Z)

增区间

π +2kπ ≤ 3x-π/3 ≤ 2π+2kπ (k∈Z)

即

π+π/3 +2kπ ≤ 3x ≤ 2π+π/3+2kπ (k∈Z)

π/3+π/9 +2kπ/3 ≤ x ≤ 2π/3+π/9+2kπ/3 (k∈Z)

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