用int Dayo Year（int year,int month,int day）；这个函数原型实现输入某年某月某

用int Dayo Year（int year,int month,int day）；这个函数原型实现输入某年某月某

int DayoYear(int year,int month,int day)

{int i,d,a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
d=day;
if(year%4==0&year%100!=0||year%400==0)a[2]++;
for(i=1;i d+=a[i];
return d;
}追问您运行过吗？运行不成啊！追答#include "stdio.h"
int DayoYear(int year,int month,int day)
{int i,d,a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
d=day;
if(year%4==0&year%100!=0||year%400==0)a[2]++;
for(i=1;id+=a[i];
return d;
}
int main()
{int y,m,d;
scanf("%d%d%d",&y,&m,&d);

printf("%d
",DayoYear(y,m,d));

return 0;

}

如以上回答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！

点此我要举报以上问答信息