编写程序实现：输入一个整数，判断它是否能被3,5,7整除，并输出以下信息之一
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解决时间 2021-11-14 20:12
- 提问者网友：椧運幽默
- 2021-11-14 07:35
编写程序实现：输入一个整数，判断它是否能被3,5,7整除，并输出以下信息之一
最佳答案
- 五星知识达人网友：末日狂欢
- 2021-11-14 07:44
char m;
scanf("%d",&m)
if (m/3=0) and (m/5=0) and (m/7=0)
printf("能同时被3,5,7整除")
else if (m/3=0) and (m/5=0) and (m/7!=0)
printf("能被3和5整除,")
else if (m/3=0) and (m/7=0) and (m/5!=0)
printf("能被3和7整除,")
else if (m/7=0) and (m/5=0) and (m/3!=0)
printf("能被7和5整除,")
else if (m/7=0) and (m/5!=0) and (m/3!=0)
printf("能被7整除,")
else if (m/7!=0) and (m/5=0) and (m/3!=0)
printf("能被5整除,")
else if (m/7!=0) and (m/5!=0) and (m/3=0)
printf("能被3整除,")
else
printf("不能被3,5,7任一个整除")
scanf("%d",&m)
if (m/3=0) and (m/5=0) and (m/7=0)
printf("能同时被3,5,7整除")
else if (m/3=0) and (m/5=0) and (m/7!=0)
printf("能被3和5整除,")
else if (m/3=0) and (m/7=0) and (m/5!=0)
printf("能被3和7整除,")
else if (m/7=0) and (m/5=0) and (m/3!=0)
printf("能被7和5整除,")
else if (m/7=0) and (m/5!=0) and (m/3!=0)
printf("能被7整除,")
else if (m/7!=0) and (m/5=0) and (m/3!=0)
printf("能被5整除,")
else if (m/7!=0) and (m/5!=0) and (m/3=0)
printf("能被3整除,")
else
printf("不能被3,5,7任一个整除")
全部回答
- 1楼网友：雪起风沙痕
- 2021-11-14 08:56
将所有情况列出，再用switch case 语句
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