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用递等式计算.①987+104×65-1747 ...

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解决时间 2021-02-12 03:03
  • 提问者网友:欺烟
  • 2021-02-11 04:54
用递等式计算.①987+104×65-1747 ②3763÷7+17×2663③(79+421-37)×6.3 ④15÷〔( 57-12)÷328〕-0.5.
最佳答案
  • 五星知识达人网友:渡鹤影
  • 2021-02-11 06:33
①987+104×65-1747,
=(1000-13)+(100+4)×65-1747,
=1000-13+6500+260-1747,
=1000-13+6500+200+60-1700-47,
=(1000+6500+200-1700)+(60-13-47),
=6000+0,
=6000;


37
63 ÷7+
1
7 ×
26
63
=
37
63 ×
1
7 +
1
7 ×
26
63 ,
=(
37
63 +
26
63 )×
1
7 ,
=1×
1
7 ,
=
1
7 ;

③(
7
9 +
4
21 -
3
7 )×6.3,
=
7
9 ×6.3+
4
21 ×6.3-
3
7 ×6.3,
=4.9+1.2-2.7,
=3.4;

④15÷[( 
5
7 -
1
2 )÷
3
28 ]-0.5,
=15÷[
3
14 ×
28
3 ]-0.5,
=15÷2-0.5,
=7.5-0.5,
=7.
全部回答
  • 1楼网友:摆渡翁
  • 2021-02-11 08:01
①987+104×65-1747, =987+(100+4)×65-1747, =987+6500+260-1747, =7747-1747, =6000; ②86.4÷3.2-6.4×3.2, =27-20.48, =6.52; ③ 37 63 ÷7+ 1 7 × 26 63 , = 37 63 × 1 7 + 1 7 × 26 63 , = 1 7 ×( 37 63 + 26 63 ), = 1 7 ; ④17-16.8÷(1.8+7.2× 1 12 ), =17-16.8÷(1.8+0.6), =17-16.8÷2.4, =17-7, =10; ⑤( 7 9 + 4 21 - 3 7 )×6.3, =6.3× 7 9 +6.3× 4 21 -6.3× 3 7 , =4.9+1.2-2.7, =3.4; ⑥15÷〔( 5 7 - 1 2 )÷ 3 28 〕-0.5, =15÷[( 5 7 - 1 2 )× 28 3 ]-0.5, =15÷[ 5 7 × 28 3 - 1 2 × 28 3 ]-0.5, =15÷[ 20 3 - 14 3 ]-0.5, =15÷2-0.5, =7.5-0.5, =7.
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