如何在python代码中跳转到函数头

答案:5 悬赏:50 手机版

解决时间 2021-01-31 02:40

提问者网友：最美的风景
2021-01-30 14:12

如何在python代码中跳转到函数头

最佳答案

五星知识达人网友：长青诗
2021-01-30 15:43

/usr/lib/python2.7
2.7也可能是3.*

文件夹里面很多 .Py 的文件和 .pyc 的文件

前者是源文件，后者已经进行了预编译

这是模块，模块中设计的函数就在里面。

比如 re、socket、string。

内建函数可能也在某个文件中，没仔细找

全部回答

1楼网友：刀戟声无边
2021-01-30 19:13

def get_omelet_ingredients(omelet_name):
ingredients = {"eggs":2,"milk":1}
if omelet_name=="cheese":
ingredients["cheddar"]=2
elif omelet_name=="western":
ingredients["jack_cheese"]=2
ingredients["ham"]=1
ingredients["pepper"]=1
ingredients["onion"]=1
elif omelet_name=="greek":
ingredients["feta_cheese"]=2
ingredients["spinach"]=2
else:
print("That's not on the menu, sorry!")
return None
return ingredients
def make_food(ingredients_needed, food_name):
for ingredient in ingredients_needed.keys():
print("Adding %d of %s to make a %s" %(ingredients_needed[ingredient], ingredient, food_name))
print("Make %s" %food_name)
return food_name
def make_omelet(omelet_type):
if type(omelet_type)==type({}):
print("omelet_type is a dictionary with ingredients")
return make_food(omelet_type, "omelet")
elif type(omelet_type)==type(""):
omelet_ingredients = get_omelet_ingredients(omelet_type)
return make_food(omelet_ingredients, omelet_type)
else:
print("I don't think I can make this kind of omelet: %s" % omelet_type)
"""利用make_omelet函数调用get_omelet_ingredients和make_food函数的值"""
omelet_type=make_omelet("cheese")

2楼网友：往事埋风中
2021-01-30 18:07

return/break/continue

3楼网友：duile
2021-01-30 16:30

方案如下：将另一个py做成一个包，或者直接和调用文件放在同一个目录下；在调用者文件头引入：from py名字 import *；这样就可以使用另一个py文件的所有函数了。

4楼网友：酒醒三更
2021-01-30 15:57

这里利用《python编程入门》书中的例子作为事例说明：
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def get_omelet_ingredients(omelet_name):
ingredients = {"eggs":2,"milk":1}
if omelet_name=="cheese":
ingredients["cheddar"]=2
elif omelet_name=="western":
ingredients["jack_cheese"]=2
ingredients["ham"]=1
ingredients["pepper"]=1
ingredients["onion"]=1
elif omelet_name=="greek":
ingredients["feta_cheese"]=2
ingredients["spinach"]=2
else:
print("That's not on the menu, sorry!")
return None
return ingredients
def make_food(ingredients_needed, food_name):
for ingredient in ingredients_needed.keys():
print("Adding %d of %s to make a %s" %(ingredients_needed[ingredient], ingredient, food_name))
print("Make %s" %food_name)
return food_name

def make_omelet(omelet_type):
if type(omelet_type)==type({}):
print("omelet_type is a dictionary with ingredients")
return make_food(omelet_type, "omelet")
elif type(omelet_type)==type(""):
omelet_ingredients = get_omelet_ingredients(omelet_type)
return make_food(omelet_ingredients, omelet_type)
else:
print("I don't think I can make this kind of omelet: %s" % omelet_type)
"""利用make_omelet函数调用get_omelet_ingredients和make_food函数的值"""
omelet_type=make_omelet("cheese")

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