1分别用while语句,do_while语句和for语句,求出N以内所有偶数的和(N由用户输入)
答案:2 悬赏:80 手机版
解决时间 2021-02-03 07:29
- 提问者网友:雪舞兮
- 2021-02-02 11:05
1分别用while语句,do_while语句和for语句,求出N以内所有偶数的和(N由用户输入)
最佳答案
- 五星知识达人网友:一叶十三刺
- 2021-02-02 12:40
#include
int main() {
int n,sum,i;
printf ("请输入整数n:");
scanf ("%d",&n);
printf ("======================================================
");
sum = 0;
i = 0;
while (i<=n) {
if (i%2==0)
sum+=i;
i++;
}
printf("while语句求和结果:%d
",sum);
sum = 0;
i = 0;
do {
if (i%2==0)
sum+=i;
i++;
} while (i<=n);
printf("do_while语句求和结果:%d
",sum);
for (i=0,sum=0; i<=n; i++)
if (i%2==0)
sum+=i;
printf("for语句求和结果:%d
",sum);
printf ("
");
getch ();
return 0;
}运行结果
int main() {
int n,sum,i;
printf ("请输入整数n:");
scanf ("%d",&n);
printf ("======================================================
");
sum = 0;
i = 0;
while (i<=n) {
if (i%2==0)
sum+=i;
i++;
}
printf("while语句求和结果:%d
",sum);
sum = 0;
i = 0;
do {
if (i%2==0)
sum+=i;
i++;
} while (i<=n);
printf("do_while语句求和结果:%d
",sum);
for (i=0,sum=0; i<=n; i++)
if (i%2==0)
sum+=i;
printf("for语句求和结果:%d
",sum);
printf ("
");
getch ();
return 0;
}运行结果
全部回答
- 1楼网友:佘樂
- 2021-02-02 13:33
int main()
{
int N = 100;
int i = 0, sum = 0;
while(i <= N)
{
sum += i;
i = i + 2;
}
}int main()
{
int N = 100;
int i = 0, sum = 0;
do
{
sum += i;
i = i + 2;
}while(i <= N);
}int main()
{
int N = 100;
int i = 0, sum = 0;
for(;i<=N;)
{
sum += i;
i = i + 2;
}
}
{
int N = 100;
int i = 0, sum = 0;
while(i <= N)
{
sum += i;
i = i + 2;
}
}int main()
{
int N = 100;
int i = 0, sum = 0;
do
{
sum += i;
i = i + 2;
}while(i <= N);
}int main()
{
int N = 100;
int i = 0, sum = 0;
for(;i<=N;)
{
sum += i;
i = i + 2;
}
}
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