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分解因式:(1) (x-y)³-(x-y) (2)x³y³-2x²y²+xy

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解决时间 2021-02-08 02:01
  • 提问者网友:末路
  • 2021-02-07 06:40
分解因式:(1) (x-y)³-(x-y) (2)x³y³-2x²y²+xy (3)a³c-4a²bc+4ab²c (4)(x²+y²)²-4x²y²
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最佳答案
  • 五星知识达人网友:人间朝暮
  • 2021-02-07 06:58

1x²y³-2x²y²+xy =xy(xy²-2xy+1)

 2 a﹙x-y﹚-b﹙y-x﹚+c﹙x-y﹚=a﹙x-y﹚+b﹙x-y﹚+c﹙x-y﹚=(a+b+c)(x-y)

[﹙x-y﹚²+﹙x+y﹚﹙x-y﹚]÷2x,=(x^2-2xy+y^2+x^2-y^2)\2x=(2x^2-2xy)\2x=x-y=3-15=-12

全部回答
  • 1楼网友:爱难随人意
  • 2021-02-07 11:00
(x-y)³-(x-y) =(x-y) {(x-y)²-1} =(x-y)(x-y-1)(x-y+1) x³y³-2x²y²+xy =xy(x²y²-2xy+1) =xy(xy-1)² a³c-4a²bc+4ab²c =ac(a²-4ab+4b²) =ac(a-2b)² (x²+y²)²-4x²y² =x^4+2x²y²+y^4-4x²y² =x^4-2x²y²+y^4 =(x²-y²)² =(x+y)²(x-y)²
  • 2楼网友:毛毛
  • 2021-02-07 09:32
(1) (x-y)³-(x-y) =(x-y)[(x-y)²-1] =(x-y)(x-y+1)(x-y-1) (2)x³y³-2x²y²+xy =xy(x²y²-2xy+1) =xy(xy-1)² (3)a³c-4a²bc+4ab²c =ac(a²-4ab+4b²) =ac(a-2b)² (4)(x²+y²)²-4x²y² =(x²+y²+2xy)(x²+y²-2xy) =(x+y)²(x-y)²
  • 3楼网友:封刀令
  • 2021-02-07 08:00
(x-y)³-(x-y)=(x-y)(x²+y²-2xy-1) x³y³-2x²y²+xy =xy(x²y²-2xy+1)=xy(xy-1)² a³c-4a²bc+4ab²c=ac(a²-4ab+4b²)=ac(a-4b)² (x²+y²)²-4x²y² =(x²+y²+2xy)(x²-2xy+y²)=(x+y)²(x-y)²
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