解方程(12x-10)/(4x-3)+(32x-34)/(8x-9)=(24x-23)/(8x-7)+(16x-19)/(4x-5)

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解决时间 2021-03-07 10:49

提问者网友：末路
2021-03-07 00:34

最佳答案

五星知识达人网友：等灯
2021-03-07 01:02

(12x-10)/(4x-3)+(32x-34)/(8x-9)=(24x-23)/(8x-7)+(16x-19)/(4x-5)

[3-1/(4x-3)]+[4+2/(8x-9)]=[3-2/(8x-7)]+[4+1/(4x-5)]

2/(8x-9)-1/(4x-3)=1/(4x-5)-2/(8x-7)

3/[(8x-9)(4x-3)]=3/[(4x-5)(8x-7)]

(4x-5)(8x-7)=(8x-9)(4x-3)

32x^2-68x+35=32x^2-60x+27

8x=8

x=1

全部回答

1楼网友：鱼芗
2021-03-07 02:13

(12x-10)/(4x-3)+(32x-34)/(8x-9)=(24x-23)/(8x-7)+(16x-19)/(4x-5)
3-1/(4x-3)+4+2/(8x-9)=3-2/(8x-7)+4+1/(4x-5)
2/(8x-9)-1/(4x-3)=1/(4x-5)-2/(8x-7)
2/(8x-9)+2/(8x-7)=1/(4x-5)+1/(4x-3)
2*16(x-1)/(8x-9)*1//(8x-7)=8(x-1)/(4x-5)*1/(4x-3)
x=1
4/(8x-9)*1/(8x-7)=1/(4x-5)*1/(4x-3)
4(4x-5)(4x-3)-(8x-9)(8x-7)=0
方程无解
最终结论 x=1
网上帮你查的，不知道看不看得懂

2楼网友：一秋
2021-03-07 01:10

(12x-10)/(4x-3)+(32x-34)/(8x-9)=(24x-23)/(8x-7)+(16x-19)/(4x-5)
3-1/(4x-3)+4+2/(8x-9)=3-2/(8x-7)+4+1/(4x-5)
2/(8x-9)-1/(4x-3)=1/(4x-5)-2/(8x-7)
[2(4x-3)-(8x-9)]/[(8x-9)(4x-3)]=[(8x-7)-2(4x-5)]/[(4x-5)(8x-7)]
3/[(8x-9)(4x-3)]=3/[(4x-5)(8x-7)]
(8x-9)(4x-3)=(4x-5)(8x-7)
x=1
代入原方程验证，x=1是原方程的解。

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