<s:select /> 传一个list值报错

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解决时间 2021-04-13 23:21

提问者网友：佞臣
2021-04-13 11:58

2010-7-3 18:02:14 org.apache.catalina.core.StandardWrapperValve invoke严重: Servlet.service() for servlet jsp threw exceptiontag 'select', field 'list', name 'typename': The requested list key '#booktypelist' could not be resolved as a collection/array/map/enumeration/iterator type. Example: people or people.{name} - [unknown location] 我booktypelist是在action 中的public String findselects() { booktypelist = (List)booktypebiz.findselect(); System.out.println(booktypelist.get(1)); System.out.println(booktypelist.size()); ActionContext.getContext().put("list", booktypelist); return "success"; } system。out。pringln都打印出来了的com.ssh.book.hibernate.BookType@b706485

最佳答案

五星知识达人网友：酒安江南
2021-04-13 12:07

system.out.println打印booktypelist当然是com.ssh.book.hibernate.BookType@b706485，因为它是一个对象，只能继续点才能有值,例:((bean的类型)booktypelist.get(1)).get属性方法,我不知道你界面是怎么写，一般是可以的，我觉的用request更好，你那个application不安全,例:HttpServletRequest request=HttpServletRequest request = ServletActionContext.getRequest();
request.setAttribute("list", booktypelist);

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1楼网友：平生事
2021-04-13 12:40

<s:select label="商品类别" list="#booktypelist" listkey="typeid" listvalue="typeid" name="typename"></s:select>

这句话有错啊，你的actioncontext.getcontext().put("list", booktypelist);你是以list为key传值到页面的，你在使用变量名booktypelist当然就不行了，你改下actioncontext.getcontext().put("booktypelist", booktypelist);在试下。

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