多项式为什么要变成切比雪夫多项式

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解决时间 2021-01-25 10:22

提问者网友：暮烟疏雨之际
2021-01-25 03:16

多项式为什么要变成切比雪夫多项式

最佳答案

五星知识达人网友：琴狂剑也妄
2021-01-25 04:20

x0),1)/
else
f = vpa(f;sqrt(1-t^2),6);t#39;pi;))*T(i)#47:k+1) = t;
c(1;sqrt(1-t^2),1)#47,t,-1,-1;
c(i) = 2*int(subs(y,x0)
syms t;
f = c(1)+c(2)*t;;

if(i==k+1)
if(nargin == 3)
f = subs(f;2,6);t#39;
T(2) = t,k,findsym(sym(y)),sym(#39;pi,#39;
f = f + c(i)*T(i),findsym(sym(y)),sym(#39,t,1)/))*T(1)#47.0;sqrt(1-t^2),findsym(sym(y));

c(1)=int(subs(y;
c(2)=2*int(subs(y,t:k+1
T(i) = 2*t*T(i-1)-T(i-2);t#39;t#39,sym(#39;

for i=3;
f = vpa(f;))*T(2)#47,-1;
T(1) = 1;
T(1用切比雪夫多项式逼近已知函数

function f = Chebyshev(y:k+1) = 0

全部回答

1楼网友：未来江山和你
2021-01-25 05:58

用切比雪夫多项式逼近已知函数 function f = chebyshev(y,k,x0) syms t; t(1:k+1) = t; t(1) = 1; t(2) = t; c(1:k+1) = 0.0; c(1)=int(subs(y,findsym(sym(y)),sym('t'))*t(1)/sqrt(1-t^2),t,-1,1)/pi; c(2)=2*int(subs(y,findsym(sym(y)),sym('t'))*t(2)/sqrt(1-t^2),t,-1,1)/pi; f = c(1)+c(2)*t; for i=3:k+1 t(i) = 2*t*t(i-1)-t(i-2); c(i) = 2*int(subs(y,findsym(sym(y)),sym('t'))*t(i)/sqrt(1-t^2),t,-1,1)/2; f = f + c(i)*t(i); f = vpa(f,6); if(i==k+1) if(nargin == 3) f = subs(f,'t',x0); else f = vpa(f,6); end end end

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