为什么request.getRemoteAddr()得到的不是数字
答案:2 悬赏:70 手机版
解决时间 2021-01-14 12:44
- 提问者网友:沦陷
- 2021-01-14 02:28
为什么request.getRemoteAddr()得到的不是数字
最佳答案
- 五星知识达人网友:琴狂剑也妄
- 2021-01-14 03:11
获得客户端真实IP二种方法!~
获得客户端真实IP地址的体例一:
public String getRemortIP(HttpServletRequest request) {
if (request.getHeader("x-forwarded-for") == null) {
return request.getRemoteAddr();
}
return request.getHeader("x-forwarded-for");
}
获得客户端真实IP地址的体例二:
public String getIpAddr(HttpServletRequest request) {
String ip = request.getHeader("x-forwarded-for");
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("Proxy-Client-IP");
}
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getRemoteAddr();
}
return ip;
}
获得客户端真实IP地址的体例一:
public String getRemortIP(HttpServletRequest request) {
if (request.getHeader("x-forwarded-for") == null) {
return request.getRemoteAddr();
}
return request.getHeader("x-forwarded-for");
}
获得客户端真实IP地址的体例二:
public String getIpAddr(HttpServletRequest request) {
String ip = request.getHeader("x-forwarded-for");
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("Proxy-Client-IP");
}
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getHeader("WL-Proxy-Client-IP");
}
if(ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
ip = request.getRemoteAddr();
}
return ip;
}
全部回答
- 1楼网友:刀戟声无边
- 2021-01-14 04:48
真不知道。别耽误你。在问问别人吧
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