springmvc controller怎么获取一个输入流

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解决时间 2021-03-10 03:10

提问者网友：箛茗
2021-03-09 19:19

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五星知识达人网友：一把行者刀
2021-03-09 19:37

springmvc 中controller获取ajax数据的方法： 1、页面jsp代码： <table style="width: 100%" class="table" cellspacing="1" cellpadding="1" border="0"> <tr><td class="ti1" colSpan="2">请选择审讯室</td></tr> <tr><td class="ti2hui">审讯室名称</td><td class="ti1cu"> <select id="roomid" name="roomid" > <c:forEach items="${roomlist}" var="room"> <option value ="${room.id}">${room.name}</option> </c:forEach> </select> </td></tr> <tr><td class="ti2hui" colSpan="2" align="center"><input type="button" onclick="setshow()" value="确定"/> </td></tr> </table> 点击确定后触发ajax接口： function setshow(){ $.ajax( { type : "POST", url : "<%=request.getContextPath()%>/initroom.do?method=set", data : { 'room' : $("#roomid").find('option:selected').text(), 'roomid' :$("#roomid").val() }, dataType: "json", success : function(data) { if(data.success){ alert("设置成功！"); } else{ alert("设置失败！"); } }, error :function(){ alert("网络连接出错！"); } }); } 2、后台controller写法： @RequestMapping(params = "method=set") public void jump(HttpSession session,HttpServletRequest request, HttpServletResponse response) throws Exception{ String roomid= request.getParameter("roomid"); String room= request.getParameter("room"); session.setAttribute("ROOMID", roomid); session.setAttribute("ROOMNAME", room); System.out.println("session set:"+room+"=="+roomid); response.setCharacterEncoding("utf-8"); response.getWriter().write("{\"success\":true }"); response.getWriter().flush(); } 3、springmvc 返回信息到ajax: import com.googlecode.jsonplugin.JSONUtil; List<Records> recordList = new ArrayList<Records>(); //获取recordlist操作省略 response.setCharacterEncoding("utf-8"); response.getWriter().write("{\"success\":true, \"data\":" + JSONUtil.serialize(recordList) + "}"); response.getWriter().flush();

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