(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(
答案:2 悬赏:50 手机版
解决时间 2021-02-15 13:20
- 提问者网友：夢醒日落
- 2021-02-14 21:08
(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(
最佳答案
- 五星知识达人网友：躲不过心动
- 2021-02-14 22:00
两边减去2(x-10)/(x-11)-1+(x-16)/(x-17)-1=(x-12)/(x-13)-1+(x-14)/(x-15)-11/(x-11)+1/(x-17)=1/(x-13)+1/(x-15)(2x-28)/(x-11)(x-17)-(2x-28)/(x-13)(x-15)=0(2x-28)[1/(x²-28x+187)-1/(x²-28x+195)=0...======以下答案可供参考======供参考答案1:答：(x-10)/(x-11)+(x-16)/(x-17)=(x-12)/(x-13)+(x-14)/(x-15)1+1/(x-11)+1+1/(x-17)=1+1/(x-13)+1+1/(x-15)1/(x-11)+1/(x-17)=1/(x-13)+1/(x-15)(x-17+x-11)/[(x-11)(x-17)]=(x-15+x-13)/[(x-13)(x-15)](2x-28)/[(x-11)(x-17)]=(2x-28)/[(x-13)(x-15)]所以：2x-28=0或者(x-11)(x-17)=(x-13)(x-15)（无解）所以：x=14经检验，x=14是原分式方程的根
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- 1楼网友：不甚了了
- 2021-02-14 23:10
这下我知道了
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