C++程序的问题
答案:6 悬赏:30 手机版
解决时间 2021-07-30 01:35
- 提问者网友：欺烟
- 2021-07-29 06:59
#include<iostream>
using namespace std;
void main()
{
double a,b,c,m,n;
char i;
cout<<"请输入a=";
cin>>a;
cout<<"请输入b=";
cin>>b;
cout<<"请输入c=";
cin>>c;
if(a=0)
cout<<"x="<<-c/b<<endl;
else
if(b*b-4*a*c==0)
cout<<"x1=x2="<<-b/2*a<<endl;
else
if(b*b-4*a*c>0)
{
m=(-b+sqrt(b*b-4*a*c))/2*a;
cout<<"x1="<<m<<endl;
n=(-b-sqrt(b*b-4*a*c))/2*a;
cout<<"x2="<<n<<endl;
}
else
{
cout<<"x1="<<-b/(2*a)<<"+"<<sqrt(b*b-4*a*c)/(2*a)<<i<<endl;
cout<<"x2="<<-b/(2*a)<<"-"<<sqrt(b*b-4*a*c)/(2*a)<<i<<endl;
}
} 错在哪
最佳答案
- 五星知识达人网友：我住北渡口
- 2021-07-29 07:28
#include<iostream>
using namespace std;
void main()
{
double a,b,c,m,n;
char i;
cout<<"请输入a=";
cin>>a;
cout<<"请输入b=";
cin>>b;
cout<<"请输入c=";
cin>>c;
if(a==0)
cout<<"x="<<-c/b<<endl;
else
if(b*b-4*a*c==0)
cout<<"x1=x2="<<-b/2*a<<endl;
else
if(b*b-4*a*c>0)
{
m=(-b+sqrt(b*b-4*a*c))/2*a;
cout<<"x1="<<m<<endl;
n=(-b-sqrt(b*b-4*a*c))/2*a;
cout<<"x2="<<n<<endl;
}
else
{
cout<<"x1="<<-b/(2*a)<<"+"<<sqrt(-(b*b-4*a*c))/(2*a)<<"i"<<endl;
cout<<"x2="<<-b/(2*a)<<"-"<<sqrt(-(b*b-4*a*c))/(2*a)<<"i"<<endl;
}
}
全部回答
- 1楼网友：低音帝王
- 2021-07-29 11:27
我在VC下面给你修改了,经测试程序能运行,并能得出正确结果,用到开平方函数一定要有#include<math.h>头文件,其次在最后的输出复数i时,前面的char i;理解有误,这只是定义了一个字符变量,里面没有任何字符,你想输出复数里的i字符,则把'i'赋予它,即char i='i';
#include<iostream>
#include<math.h>
using namespace std;
void main()
{
double a,b,c,m,n;
char i='i';
cout<<"请输入a=";
cin>>a;
cout<<"请输入b=";
cin>>b;
cout<<"请输入c=";
cin>>c;
if(a==0)
cout<<"x="<<-c/b<<endl;
else
if(b*b-4*a*c==0)
cout<<"x1=x2="<<-b/(2*a)<<endl;
else
if(b*b-4*a*c>0)
{
m=(-b+sqrt(b*b-4*a*c))/(2*a);
cout<<"x1="<<m<<endl;
n=(-b-sqrt(b*b-4*a*c))/(2*a);
cout<<"x2="<<n<<endl;
}
else
{
cout<<"x1="<<-b/(2*a)<<"+"<<sqrt(-(b*b-4*a*c))/(2*a)<<i<<endl;
cout<<"x2="<<-b/(2*a)<<"-"<<sqrt(-(b*b-4*a*c))/(2*a)<<i<<endl;
}
- 3楼网友：千杯敬自由
- 2021-07-29 10:21
根据我得理解，这应该是个解一次和二次方程的程序，a,b,c为方程参数。以下是改好了的程序：#include<iostream>#include<cmath>using namespace std;void main(){ double a,b,c,m,n; cout<<"请输入a="; cin>>a; cout<<"请输入b="; cin>>b; cout<<"请输入c="; cin>>c; if(a==0) cout<<"x="<<-c/b<<endl; else if(b*b-4*a*c==0) cout<<"x1=x2="<<-b/2*a<<endl; else if(b*b-4*a*c>0) { m=(-b+sqrt(b*b-4*a*c))/2*a; cout<<"x1="<<m<<endl; n=(-b-sqrt(b*b-4*a*c))/2*a; cout<<"x2="<<n<<endl; } else { cout<<"x1="<<-b/(2*a)<<"+"<<sqrt(4*a*c-b*b)/(2*a)<<'i'<<endl; cout<<"x2="<<-b/(2*a)<<"-"<<sqrt(4*a*c-b*b)/(2*a)<<'i'<<endl; }}
错误如下：1.没有#include<cmath>，因为用sqrt这类数学函数，都要#include<cmath>；2.第一个if 函数条件内：a=0,应该为a==0,相信这是楼主笔误，要仔细呀；3.对于输出虚数i，不必用char i，直接在cout<<'i'就可以了；4.当解为虚数时，不要输出sqrt(b*b-4*a*c)/(2*a)，改为输出sqrt(4*a*c-b*b)/(2*a)；
- 4楼网友：孤老序
- 2021-07-29 09:13
错误太多了，看加粗的部分吧：
#include<iostream>
#include<math.h>
using namespace std;
int main()
{
double a,b,c,m,n;
char i = 'i';
cout<<"请输入a=";
cin>>a;
cout<<"请输入b=";
cin>>b;
cout<<"请输入c=";
cin>>c;
if(a==0)
cout<<"x="<<-c/b<<endl;
else
if(b*b-4*a*c==0)
cout<<"x1=x2="<<-b/2*a<<endl;
else
if(b*b-4*a*c>0)
{
m=(-b+sqrt(b*b-4*a*c))/2*a;
cout<<"x1="<<m<<endl;
n=(-b-sqrt(b*b-4*a*c))/2*a;
cout<<"x2="<<n<<endl;
}
else
{
cout<<"x1="<<-b/(2*a)<<"+"<<sqrt(-(b*b-4*a*c))/(2*a)<<i<<endl;
cout<<"x2="<<-b/(2*a)<<"-"<<sqrt(-(b*b-4*a*c))/(2*a)<<i<<endl;
}
}
- 5楼网友：酒醒三更
- 2021-07-29 07:42
#include<iostream>
#include<cmath> //sqrt()
using namespace std;
void main()
{
double a,b,c,m,n;
char i;
cout<<"请输入a=";
cin>>a;
cout<<"请输入b=";
cin>>b;
cout<<"请输入c=";
cin>>c;
if(a==0) //判断相等用== 赋值才用=
cout<<"x="<<-c/b<<endl;
else
if(b*b-4*a*c==0)
cout<<"x1=x2="<<-b/2*a<<endl;
else
if(b*b-4*a*c>0)
{
m=(-b+sqrt(b*b-4*a*c))/2*a;
cout<<"x1="<<m<<endl;
n=(-b-sqrt(b*b-4*a*c))/2*a;
cout<<"x2="<<n<<endl;
}
else
{
cout<<"x1="<<-b/(2*a)<<"+"<<sqrt(b*b-4*a*c)/(2*a)<<i<<endl;
cout<<"x2="<<-b/(2*a)<<"-"<<sqrt(b*b-4*a*c)/(2*a)<<i<<endl;
}
}
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