已知tanx=3/4,求1/4sinx+2/5cosx的值
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解决时间 2021-01-21 06:29
- 提问者网友:太高姿态
- 2021-01-20 19:05
已知tanx=3/4,求1/4sinx+2/5cosx的值
最佳答案
- 五星知识达人网友:举杯邀酒敬孤独
- 2021-01-20 19:49
答案是:47/100 或者-47/100
tanx=3/4 = sinx/cosx又sin²x + cos²x =1
可得 sinx= 3/5,cosx=4/5,或sinx= -3/5,cosx= -4/5
1/4sinx+2/5cosx=1/4x3/5+2/5x4/5=3/20+8/25=15/100+32/100=47/100
或者:1/4sinx+2/5cosx=-1/4x3/5-2/5x4/5=-15/100-32/100=-47/100
希望帮到你 望采纳 谢谢 加油
tanx=3/4 = sinx/cosx又sin²x + cos²x =1
可得 sinx= 3/5,cosx=4/5,或sinx= -3/5,cosx= -4/5
1/4sinx+2/5cosx=1/4x3/5+2/5x4/5=3/20+8/25=15/100+32/100=47/100
或者:1/4sinx+2/5cosx=-1/4x3/5-2/5x4/5=-15/100-32/100=-47/100
希望帮到你 望采纳 谢谢 加油
全部回答
- 1楼网友:神的生死簿
- 2021-01-20 21:50
算出4个解的那煞笔也是逗死我了
- 2楼网友:你哪知我潦倒为你
- 2021-01-20 21:25
tanx =3/4
sinx = ±3/5
cosx = ±4/5
case 1: sinx=3/5 , cosx =4/5
(1/4)sinx+(2/5)cosx
=(1/4)(3/5)+(2/5)(4/5)
=3/20+ 8/25
=(15+32)/100
=47/100
case 2: sinx=3/5 , cosx =-4/5
(1/4)sinx+(2/5)cosx
=(1/4)(3/5)+(2/5)(-4/5)
=3/20- 8/25
=(15-32)/100
=-17/100
case 3: sinx=-3/5 , cosx =4/5
(1/4)sinx+(2/5)cosx
=(1/4)(-3/5)+(2/5)(4/5)
=-3/20+ 8/25
=(-15+32)/100
=17/100
case 1: sinx=-3/5 , cosx =-4/5
(1/4)sinx+(2/5)cosx
=(1/4)(-3/5)+(2/5)(-4/5)
=-3/20- 8/25
=(-15-32)/100
=-47/100
ie
(1/4)sinx+(2/5)cosx = ±17/100 , ±47/100
sinx = ±3/5
cosx = ±4/5
case 1: sinx=3/5 , cosx =4/5
(1/4)sinx+(2/5)cosx
=(1/4)(3/5)+(2/5)(4/5)
=3/20+ 8/25
=(15+32)/100
=47/100
case 2: sinx=3/5 , cosx =-4/5
(1/4)sinx+(2/5)cosx
=(1/4)(3/5)+(2/5)(-4/5)
=3/20- 8/25
=(15-32)/100
=-17/100
case 3: sinx=-3/5 , cosx =4/5
(1/4)sinx+(2/5)cosx
=(1/4)(-3/5)+(2/5)(4/5)
=-3/20+ 8/25
=(-15+32)/100
=17/100
case 1: sinx=-3/5 , cosx =-4/5
(1/4)sinx+(2/5)cosx
=(1/4)(-3/5)+(2/5)(-4/5)
=-3/20- 8/25
=(-15-32)/100
=-47/100
ie
(1/4)sinx+(2/5)cosx = ±17/100 , ±47/100
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