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C#如何给文件重命名

答案:2  悬赏:10  手机版
解决时间 2021-02-16 05:50
  • 提问者网友:骨子里的高雅
  • 2021-02-15 21:34
我生成的文件在temp下,每次把文件copy到back下,在把temp的文件删掉,怎么样才能把back中复制过来的的文件重命名,temp下的文件名格式都为 YYYYMMdd.txtd的,所以如何判断back下是否有相同的文件,然后再重命名。(最少10次)
最佳答案
  • 五星知识达人网友:琴狂剑也妄
  • 2021-02-15 21:59
我写了个winform的控制台应用程序。你看看。 static void Main(string[] args)
{
string path = @"d:\4.txt"; //源文件
string path2 = @"d:\move1\3.txt";//移动到哪里
if (MoveFile(path, path2))
Console.WriteLine("success");
else
Console.WriteLine("bad"); Console.WriteLine();
}
private static bool MoveFile(string OldPath, string MoveNewPath)
{
Boolean IsSuccess = false;//状态 try
{
if (!File.Exists(OldPath))//判断路径是是否存在
{
Console.WriteLine("不存在,正在创建");
using (FileStream fs = File.Create(OldPath)) { } //创建文件
}
if (!File.Exists(MoveNewPath))//判断路径是是否存在
{
Console.WriteLine("不存在,正在创建");
using (FileStream fs = File.Create(MoveNewPath)) { } //创建文件
}
if (File.Exists(MoveNewPath))
{
Console.WriteLine("原目录有相同的文件,/r是否覆盖该文件,确定:Y 取消输入:N");
string inputVlaue = Console.ReadLine();
switch (inputVlaue.ToUpper())
{
case "Y":
File.Delete(MoveNewPath);
File.Move(OldPath, MoveNewPath);
IsSuccess = true;
Console.WriteLine("成功将{0}move到{1}.", OldPath, MoveNewPath);
break;
case "N":
IsSuccess = false;
break;
default:
Console.WriteLine("输入有误");
break;
}
}
else
{
File.Move(OldPath, MoveNewPath);
IsSuccess = true;
}
}
catch (Exception e)
{
Console.WriteLine("The process failed: {0}", e.ToString());
}
return IsSuccess;
}
全部回答
  • 1楼网友:鸠书
  • 2021-02-15 23:28
用file.move 原形: public static void move ( string sourcefilename, string destfilename ) 参数 sourcefilename 要移动的文件的名称。 destfilename 文件的新路径。 using system; using system.io; class test { public static void main() { string path = @"c:\temp\mytest.txt"; string path2 = @"c:\temp2\mytest.txt"; try { if (!file.exists(path)) { // this statement ensures that the file is created, // but the handle is not kept. using (filestream fs = file.create(path)) {} } // ensure that the target does not exist. if (file.exists(path2)) file.delete(path2); // move the file. file.move(path, path2); console.writeline("{0} was moved to {1}.", path, path2); // see if the original exists now. if (file.exists(path)) { console.writeline("the original file still exists, which is unexpected."); } else { console.writeline("the original file no longer exists, which is expected."); } } catch (exception e) { console.writeline("the process failed: {0}", e.tostring()); } } }
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