当x*x-4x+1=0是,求x*x/x-1-(1+1/x*x-x)的值
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解决时间 2021-04-01 19:31
- 提问者网友：寂寞撕碎了回忆
- 2021-03-31 21:52
当x*x-4x+1=0是,求x*x/x-1-(1+1/x*x-x)的值
最佳答案
- 五星知识达人网友：妄饮晩冬酒
- 2019-12-06 02:07
x*x/x-1-(1+1/x*x-x)
=x²/(x-1)-(x²-x+1)/x(x-1)
=(x³-x²+x-1)/x(x-1)
=[x²(x-1)+(x-1)]/x(x-1)
=(x-1)(x²+1)/x(x-1)
=(x²+1)/x
=(x²-4x+1+4x)/x
=4x/x
=4
=x²/(x-1)-(x²-x+1)/x(x-1)
=(x³-x²+x-1)/x(x-1)
=[x²(x-1)+(x-1)]/x(x-1)
=(x-1)(x²+1)/x(x-1)
=(x²+1)/x
=(x²-4x+1+4x)/x
=4x/x
=4
全部回答
- 1楼网友：舊物识亽
- 2021-02-10 12:21
x*x-4x+1=0
x^2-4x+1=0
x^2+1=4x
显然x≠0
所以x+1/x=4
平方
x^2+2+1/x^2=16
x^2-2+1/x^2=12
(x-1/x)^2=12
x-1/x=±2√3
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