1/3x1+1/4x2+1/5x3+1/6x4+······+1/22x20=
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解决时间 2021-01-24 12:29
- 提问者网友：嘚啵嘚啵
- 2021-01-24 07:50
1/3x1+1/4x2+1/5x3+1/6x4+······+1/22x20=
最佳答案
- 五星知识达人网友：底特律间谍
- 2021-01-24 08:53
1/3x1+1/4x2+1/5x3+1/6x4+······+1/22x20=
1/3x(3-2)+1/4x(4-2)+1/5x(5-2)+1/6x(6-2)+······+1/22x(22-2)=
(1-2/3)+(1-2/4)+(1-2/5)+.......+(1-2/22)=
22-2*(1/3+1/4+1/5+,,,,,,+1/22)还得手算
1/3+1/4+1/5+,,,,,,+1/22+,,,,1/n 此为调和集数，趋于无穷。
1/3x(3-2)+1/4x(4-2)+1/5x(5-2)+1/6x(6-2)+······+1/22x(22-2)=
(1-2/3)+(1-2/4)+(1-2/5)+.......+(1-2/22)=
22-2*(1/3+1/4+1/5+,,,,,,+1/22)还得手算
1/3+1/4+1/5+,,,,,,+1/22+,,,,1/n 此为调和集数，趋于无穷。
全部回答
- 1楼网友：归鹤鸣
- 2021-01-24 10:04
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