已知(a-1)²+|ab-2|=0,求下面算式的值
答案:6 悬赏:80 手机版
解决时间 2021-04-02 11:43
- 提问者网友:听门外雪花风
- 2021-04-01 19:50
已知(a-1)²+|ab-2|=0,求下面算式的值
最佳答案
- 五星知识达人网友:罪歌
- 2021-04-01 20:05
因为绝对值与平方的非负性,可知:ab+2=0a+1=0故:a=-1 b=2故:1/(a-1)(b+1)+1/(a-2)(b+2)+……+1/(a-100)(b+100) =-(1/2*3+1/3*1/4+……+1/101*1/102) =-(1/2-1/3+1/3-1/4+……+1/101-1/102) =-(1/2-1/102) =-50/102 =-25/51
全部回答
- 1楼网友:像个废品
- 2021-04-02 01:30
因为绝对值与平方的非负性,可知:ab+2=0a+1=0故:a=-1 b=2故:1/(a-1)(b+1)+1/(a-2)(b+2)+……+1/(a-100)(b+100) =-(1/2*3+1/3*1/4+……+1/101*1/102) =-(1/2-1/3+1/3-1/4+……+1/101-1/102) =-(1/2-1/102) =-50/102 =-25/51
- 2楼网友:走死在岁月里
- 2021-04-02 00:06
因为绝对值与平方的非负性,可知:ab+2=0a+1=0故:a=-1 b=2故:1/(a-1)(b+1)+1/(a-2)(b+2)+……+1/(a-100)(b+100) =-(1/2*3+1/3*1/4+……+1/101*1/102) =-(1/2-1/3+1/3-1/4+……+1/101-1/102) =-(1/2-1/102) =-50/102 =-25/51
- 3楼网友:慢性怪人
- 2021-04-01 22:33
因为绝对值与平方的非负性,可知:ab+2=0a+1=0故:a=-1 b=2故:1/(a-1)(b+1)+1/(a-2)(b+2)+……+1/(a-100)(b+100) =-(1/2*3+1/3*1/4+……+1/101*1/102) =-(1/2-1/3+1/3-1/4+……+1/101-1/102) =-(1/2-1/102) =-50/102 =-25/51
- 4楼网友:北城痞子
- 2021-04-01 22:23
因为绝对值与平方的非负性,可知:ab+2=0a+1=0故:a=-1 b=2故:1/(a-1)(b+1)+1/(a-2)(b+2)+……+1/(a-100)(b+100) =-(1/2*3+1/3*1/4+……+1/101*1/102) =-(1/2-1/3+1/3-1/4+……+1/101-1/102) =-(1/2-1/102) =-50/102 =-25/51
- 5楼网友:掌灯师
- 2021-04-01 21:05
因为绝对值与平方的非负性,可知:ab+2=0a+1=0故:a=-1 b=2故:1/(a-1)(b+1)+1/(a-2)(b+2)+……+1/(a-100)(b+100) =-(1/2*3+1/3*1/4+……+1/101*1/102) =-(1/2-1/3+1/3-1/4+……+1/101-1/102) =-(1/2-1/102) =-50/102 =-25/51
我要举报
如以上回答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息,可以点下面链接进行举报!
点此我要举报以上问答信息
大家都在看
推荐资讯