已知X2-2X=2, 求(X-1)2+(X+3)(X-3)+(X-3)(X-1)的值
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解决时间 2021-01-25 18:31
- 提问者网友：感性作祟
- 2021-01-25 06:38
已知X2-2X=2, 求(X-1)2+(X+3)(X-3)+(X-3)(X-1)的值
最佳答案
- 五星知识达人网友：冷風如刀
- 2021-01-25 07:11
(X-1)2+(X+3)(X-3)+(X-3)(X-1)
=(X-1)2+(X+3+X-1)(X-3)
=(X-1)^2+2(X+1)(X-3)
=X^2-2X+1+2(X^2-2X-3)
=2+1+2(2-3)
=1
=(X-1)2+(X+3+X-1)(X-3)
=(X-1)^2+2(X+1)(X-3)
=X^2-2X+1+2(X^2-2X-3)
=2+1+2(2-3)
=1
全部回答
- 1楼网友：duile
- 2021-01-25 08:33
(X-1)2+(X+3)(X-3)+(X-3)(X-1)
=(X-1)2+(X+3+X-1)(X-3)
=(X-1)^2+2(X+1)(X-3)
=X^2-2X+1+2(X^2-2X-3)
=2+1+2(2-3)
=1
就这样
=(X-1)2+(X+3+X-1)(X-3)
=(X-1)^2+2(X+1)(X-3)
=X^2-2X+1+2(X^2-2X-3)
=2+1+2(2-3)
=1
就这样
- 2楼网友：忘川信使
- 2021-01-25 07:43
(X-1)(X-1)+(X+3)(X-3)+(X-3)(X-1)
=XX-2X+1+XX-9+XX-4X+3
=3XX-6X-5
=3(XX-2X)-5
=3*2-5
=1
=XX-2X+1+XX-9+XX-4X+3
=3XX-6X-5
=3(XX-2X)-5
=3*2-5
=1
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