溶解0.02mol/lmns需要0.1l多少浓度的hacKspMnS＝4.65×10的负14次方
答案:1 悬赏:0 手机版
解决时间 2021-02-11 07:46
- 提问者网友：了了无期
- 2021-02-10 10:54
溶解0.02mol/lmns需要0.1l多少浓度的hacKspMnS＝4.65×10的负14次方
最佳答案
- 五星知识达人网友：罪歌
- 2021-02-10 12:02
[Mn2+] ==0.01mol/L
[S2-]==4.65*10^-14/0.01 == 4.65*10^-12mol/L
H2S<==> 2H+ + S2-
Ka==[H+]^2 *[S2-]/[H2S] ==[H+]^2 *[S2-]*[HS-]/[H2S]*[HS-] ==Ka1*Ka2
[H+] ==(9.1*1.1*10^-20*0.1/4.65*10^-12)^1/2 == 4.69*10^-5mol/L
[H+] ==(KaC)^1/2
C == [H+]^2/Ka ==4.65*10^-5mol/L
[S2-]==4.65*10^-14/0.01 == 4.65*10^-12mol/L
H2S<==> 2H+ + S2-
Ka==[H+]^2 *[S2-]/[H2S] ==[H+]^2 *[S2-]*[HS-]/[H2S]*[HS-] ==Ka1*Ka2
[H+] ==(9.1*1.1*10^-20*0.1/4.65*10^-12)^1/2 == 4.69*10^-5mol/L
[H+] ==(KaC)^1/2
C == [H+]^2/Ka ==4.65*10^-5mol/L
我要举报
如以上回答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！
点此我要举报以上问答信息
大家都在看
推荐资讯