用定积分的换元法计算∫sin(x+π/3)dx,上限为π,下限为π/3
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解决时间 2021-03-24 04:02
- 提问者网友：暗中人
- 2021-03-23 09:11
用定积分的换元法计算∫sin(x+π/3)dx,上限为π,下限为π/3
最佳答案
- 五星知识达人网友：西岸风
- 2021-03-23 10:24
[π/3,π] ∫ sin(x+π/3)dx
= - cos(x+π/3) | [π/3,π]
= cos(π/3 + π/3) - cos(π + π/3)
= - 1/2 - (-1/2)
= 0
= - cos(x+π/3) | [π/3,π]
= cos(π/3 + π/3) - cos(π + π/3)
= - 1/2 - (-1/2)
= 0
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