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请老师编辑选股源码,要求选出0轴之上出现的所有红箭头(0轴下的不要)

答案:2  悬赏:80  手机版
解决时间 2021-01-27 13:38
  • 提问者网友:临风不自傲
  • 2021-01-26 13:48
{参数N为5,10,5} DIFIF1:=EMA(CLOSE,12) - EMA(CLOSE,26); DEAEA1:=EMA(DIFIF1,9); MACD1=2*(DIFIF1-DEAEA1),STICK; MACD2:=EMA(MACD1,3); STICKLINE(MACD1>MACD2 AND MACD1>0,0,MACD1,1,0),COLORRED; STICKLINE(MACD1>MACD2 AND MACD1<0,0,MACD1,1,0),COLORGREEN; STICKLINE(MACD1=0 OR MACD1<=0,0,0,50,1),COLORWHITE; DIFIF1,COLOR33FF33,LINETHICK2; DEAEA1,COLORYELLOW,LINETHICK2; MACD:MACD1,NODRAW,COLORMAGENTA; 强:IF(DIFIF1>=DEAEA1,DIFIF1,DRAWNULL),COLORRED,LINETHICK2; 弱:=IF(DEAEA1>=DIFIF1,DEAEA1,DRAWNULL),COLORFF9900,LINETHICK2; DRAWICON(CROSS(DIFIF1,DEAEA1),DIFIF1+0.1,1); DRAWICON(CROSS(DEAEA1,DIFIF1),0.4,2); A1:=BARSLAST(REF(CROSS("MACD.DIF","MACD.DEA"),1)); B1:=REF(C,A1+1)>C AND REF("MACD.DIF",A1+1)<"MACD.DIF" AND CROSS("MACD.DIF","MACD.DEA"); DRAWTEXT(B1>0,-0.8,'MACD底背'),COLORFF00FF; A2:=BARSLAST(REF(CROSS("KDJ.K","KDJ.D"),1)); B2:=REF(C,A2+1)>C AND REF("KDJ.K",A2+1)<"KDJ.K" AND CROSS("KDJ.K","KDJ.D"); DRAWTEXT(B2,-0.6,'KDJ底离'),COLORYELLOW;{KDJ底背离}; A3:=BARSLAST(REF(CROSS("RSI.RSI1","RSI.RSI2"),1)); B3:=REF(C,A3+1)>C AND REF("RSI.RSI1",A3+1)<"RSI.RSI1" AND CROSS("RSI.RSI1","RSI.RSI2"); DRAWTEXT(B3>0,-0.3,'RSI底离'),COLORCYAN;{RSI底背离}; C1:=BARSLAST(REF(CROSS("MACD.DEA","MACD.DIF"),1)); D1:=REF(C,C1+1)"MACD.DIF" AND CROSS("MACD.DEA","MACD.DIF"); DRAWTEXT(D1>0,0.4,'MACD顶离'),COLORBLUE;{MACD顶背离} C2:=BARSLAST(REF(CROSS("KDJ.D","KDJ.K"),1)); D2:=REF(C,C2+1)"KDJ.K" AND CROSS("KDJ.D","KDJ.K"); DRAWTEXT(D2>0,0.6,'KDJ顶离'),COLORLIGRAY;{KDJ顶背离} C3:=BARSLAST(REF(CROSS("RSI.RSI2","RSI.RSI1"),1)); D3:=REF(C,C3+1)"RSI.RSI1" AND CROSS("RSI.RSI2","RSI.RSI1"); DRAWTEXT(D3>0,0.8,'RSI顶离'),COLORGREEN;{RSI顶背离};
最佳答案
  • 五星知识达人网友:玩世
  • 2021-01-26 13:56
{参数N为5,10,5}
DIFIF1:=EMA(CLOSE,12) - EMA(CLOSE,26);
DEAEA1:=EMA(DIFIF1,9);
CROSS(DIFIF1,DEAEA1)
AND DEAEA1>0 AND DIFIF1>0;
全部回答
  • 1楼网友:从此江山别
  • 2021-01-26 15:04
搜一下:请老师编辑选股源码,要求选出0轴之上出现的所有红箭头(0轴下的不要)
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