dx/(x-1)乘以(x-2)乘以(x-3)的不定积分是什么 答案是1/2ln((x-1)（x-
答案:1 悬赏:20 手机版
解决时间 2021-03-10 20:36
- 提问者网友：却不属于对方
- 2021-03-10 11:55
dx/(x-1)乘以(x-2)乘以(x-3)的不定积分是什么 答案是1/2ln((x-1)（x-
最佳答案
- 五星知识达人网友：迟山
- 2021-03-10 12:40
1/[(x-1)(x-2)(x-3)]≡A/(x-1)+B/(x-2)+C/(x-3)
=>
1≡A(x-2)(x-3)+B(x-1)(x-3)+C(x-1)(x-2)
x=1, A= 1/2
x=2, B= -1
x=3, C=1/2
∫ dx/[(x-1)(x-2)(x-3)]
=(1/2)∫ [1/(x-1) -2/(x-2)+1/(x-3)] dx
=(1/2)ln|(x-1)(x-3)/(x-2)^2| + C
=>
1≡A(x-2)(x-3)+B(x-1)(x-3)+C(x-1)(x-2)
x=1, A= 1/2
x=2, B= -1
x=3, C=1/2
∫ dx/[(x-1)(x-2)(x-3)]
=(1/2)∫ [1/(x-1) -2/(x-2)+1/(x-3)] dx
=(1/2)ln|(x-1)(x-3)/(x-2)^2| + C
我要举报
如以上回答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息，可以点下面链接进行举报！
点此我要举报以上问答信息
大家都在看
推荐资讯