c=2*(r[2*k+2]-0;
for(k=1,&N),&S;%f;math,%d\}}}
F=NIN/,M;
y1=y0+d*s*sin(p);0) continue;
a=pow((M*S);r[k]=rand()/,p.h>3;
scanf("
x0=(r[0]-0.5);
for(j=0,1;
d=r[k+6];
y0=(r[1]-0;
for(i=0;n"
int NIN.h>.0/32767;stdio;
s=sqrt(1-c*c);i<2)>,%f.14*r[2*k+1],S;
void main()
{float M,N;;time;9;end\.0/.5););3,a;
#include<,M,%f,y0;n"),%d"
#include
srand((unsigned)time(NULL)),S.5),z0.5).0);
if(abs(F-1)<,&EP,%f,y1;n"S/,c;j++)
{int i;2)>,x1;b=pow((M/j<,EP,x0;k<,b,%f\,S\,j;
else if((abs(z1)-b/;
printf(",EP;2)>=2.h>,%f,N);N;
else if((abs(y1)-a/reput M,&M;float r[9];
if((abs(x1)-a/
x1=x0+d*s*cos(p),d;0) continue.0);
z0=(r[2]-0,z1;
printf(",1;
z1=z0+d*c;
else printf(",S);S);i++)
{k=i,F;int k;n"%f#include<
else NIN=NIN+1;k++)
{p=2*3.0;
#include<
郁闷了我还有张这个程序的流程图。。,可是上传不了