已知x^2m=2,y^n=3.求(1)(x^2)^2m;(2)x^6my^3n
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解决时间 2021-11-24 02:34
- 提问者网友：嘚啵嘚啵
- 2021-11-23 06:47
已知x^2m=2,y^n=3.求(1)(x^2)^2m;(2)x^6my^3n
最佳答案
- 五星知识达人网友：第幾種人
- 2021-11-23 08:03
解
x^2m=2,y^n=3
∴(x²)^2m
=(x^2m)²
=2²
=4
x^6m×y^3n
=(x^2m×y^n)³
=(2×3)³
=6³
=216
x^2m=2,y^n=3
∴(x²)^2m
=(x^2m)²
=2²
=4
x^6m×y^3n
=(x^2m×y^n)³
=(2×3)³
=6³
=216
全部回答
- 1楼网友：从此江山别
- 2021-11-23 09:06
(1)(x^2)^2m;
=(x^2m)^2
=2^2
=4
(2)x^6my^3n
=[(x^2m)^3]*[(y^n)^3]
=(2^3)*(3^3)
=8*27
=216
=(x^2m)^2
=2^2
=4
(2)x^6my^3n
=[(x^2m)^3]*[(y^n)^3]
=(2^3)*(3^3)
=8*27
=216
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