已知lg2=a,lg3=b,求下列格式的值
(1)lg16 (2)log3(4)
(3)log2(12) lg3/2
要有过程
(1)lg16=4lg2=4a
(2)log3(4)=lg4/lg3=2lg2/lg3=2a/b
(3)log2(12) lg3/2=[(lg3+2lg2)/lg2](lg3-lg2)=[(b+2a)/a](b-a)