求高手把通达信的换手率改编成柱状图
答案:2 悬赏:20 手机版
解决时间 2021-04-15 08:17
- 提问者网友:练爱
- 2021-04-14 15:30
求高手把通达信的换手率改编成柱状图
最佳答案
- 五星知识达人网友:由着我着迷
- 2021-04-14 17:04
换手:VOL/CAPITAL*100,VOLSTICK;
均五:MA(换手,5),COLORWHITE,LINETHICK2,NODRAW;
均十:MA(换手,10),COLORMAGENTA,LINETHICK2,NODRAW;
均20换:MA(换手,20),COLORGREEN,LINETHICK2,NODRAW;
地量1:换手<1,COLORWHITE,NODRAW;
低靡1到2:换手>=1 AND 换手<2, COLORGRAY,NODRAW;
温活2到3:换手>=2 AND 换手<3,COLORCYAN,NODRAW;
活跃3到5:换手>=3 AND 换手<5,COLORYELLOW,NODRAW;
带量5到8:换手>=5 AND 换手<8,COLORMAGENTA,NODRAW;
放量8到15:换手>=8 AND 换手<15,COLORRED,NODRAW;
巨量15到25:换手>=15 AND 换手<25,COLORBROWN,NODRAW;
怪异超25:换手>=25,COLORBLUE,NODRAW;
STICKLINE(换手<1,0,换手,2.3,0),COLORWHITE;
STICKLINE(换手>=1 AND 换手<2,0,换手,2,0),COLORGRAY;
STICKLINE(换手>=2 AND 换手<3,0,换手,2,0)COLORCYAN;
STICKLINE(换手>=3 AND 换手<5,0,换手,2,0)COLORYELLOW;
STICKLINE(换手>=5 AND 换手<8,0,换手,2,0)COLORMAGENTA;
STICKLINE(换手>=8 AND 换手<15,0,换手,2,0)COLORRED;
STICKLINE(换手>=15 AND 换手<25,0,换手,2,0),COLORBROWN;
STICKLINE(换手>=25,0,换手,2,0),COLORBLUE;
均5:MA(换手,5),COLORWHITE,LINETHICK2,NODRAW;
均10:MA(换手,10),COLORMAGENTA,LINETHICK2;
均20:MA(换手,20),COLORGREEN,LINETHICK2;
均换5:MA(换手,5)COLORWHITE,LINETHICK2;
IF(均换5>REF(均换5,1),均换5,DRAWNULL), COLORRED,LINETHICK3;
均换60:MA(换手,60)POINTDOT,COLORBLUE, LINETHICK4;
均五:MA(换手,5),COLORWHITE,LINETHICK2,NODRAW;
均十:MA(换手,10),COLORMAGENTA,LINETHICK2,NODRAW;
均20换:MA(换手,20),COLORGREEN,LINETHICK2,NODRAW;
地量1:换手<1,COLORWHITE,NODRAW;
低靡1到2:换手>=1 AND 换手<2, COLORGRAY,NODRAW;
温活2到3:换手>=2 AND 换手<3,COLORCYAN,NODRAW;
活跃3到5:换手>=3 AND 换手<5,COLORYELLOW,NODRAW;
带量5到8:换手>=5 AND 换手<8,COLORMAGENTA,NODRAW;
放量8到15:换手>=8 AND 换手<15,COLORRED,NODRAW;
巨量15到25:换手>=15 AND 换手<25,COLORBROWN,NODRAW;
怪异超25:换手>=25,COLORBLUE,NODRAW;
STICKLINE(换手<1,0,换手,2.3,0),COLORWHITE;
STICKLINE(换手>=1 AND 换手<2,0,换手,2,0),COLORGRAY;
STICKLINE(换手>=2 AND 换手<3,0,换手,2,0)COLORCYAN;
STICKLINE(换手>=3 AND 换手<5,0,换手,2,0)COLORYELLOW;
STICKLINE(换手>=5 AND 换手<8,0,换手,2,0)COLORMAGENTA;
STICKLINE(换手>=8 AND 换手<15,0,换手,2,0)COLORRED;
STICKLINE(换手>=15 AND 换手<25,0,换手,2,0),COLORBROWN;
STICKLINE(换手>=25,0,换手,2,0),COLORBLUE;
均5:MA(换手,5),COLORWHITE,LINETHICK2,NODRAW;
均10:MA(换手,10),COLORMAGENTA,LINETHICK2;
均20:MA(换手,20),COLORGREEN,LINETHICK2;
均换5:MA(换手,5)COLORWHITE,LINETHICK2;
IF(均换5>REF(均换5,1),均换5,DRAWNULL), COLORRED,LINETHICK3;
均换60:MA(换手,60)POINTDOT,COLORBLUE, LINETHICK4;
全部回答
- 1楼网友:迷人又混蛋
- 2021-04-14 18:02
{N1=5,N2=13,N3=25。};
AT:IF(CAPITAL=0,AMOUNT/100000000,VOL/CAPITAL*100),VOLSTICK;
{指数为成交金额,个股为换手率}
ATM1:EMA(AT,N1);
ATM2:MA(AT,N2);
T%D:SUMBARS(VOL,CAPITAL),NODRAW;
{换手率达到100%的交易日天数};
阶段天量:=AT>REF(HHV(AT,N3),1) && ATM1>ATM2;
阶段地量:=ATSTICKLINE(阶段天量,0,AT*0.75,0.35,0),COLORCC66FF;
STICKLINE(阶段地量,0,AT*0.75,2.38,0),COLOR009900;
STICKLINE(阶段地量,0,AT*0.75,0.35,0),COLOR00FF00;
AT:IF(CAPITAL=0,AMOUNT/100000000,VOL/CAPITAL*100),VOLSTICK;
{指数为成交金额,个股为换手率}
ATM1:EMA(AT,N1);
ATM2:MA(AT,N2);
T%D:SUMBARS(VOL,CAPITAL),NODRAW;
{换手率达到100%的交易日天数};
阶段天量:=AT>REF(HHV(AT,N3),1) && ATM1>ATM2;
阶段地量:=ATSTICKLINE(阶段天量,0,AT*0.75,0.35,0),COLORCC66FF;
STICKLINE(阶段地量,0,AT*0.75,2.38,0),COLOR009900;
STICKLINE(阶段地量,0,AT*0.75,0.35,0),COLOR00FF00;
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