如何用正则匹配a标签的属性

例如dsaqsavsa 如何取得href里的属性以及取得这里面的字符串

C#代码,需要using System.Text.RegularExpressions; string linkA = string.Empty;
string textA = string.Empty; string m="qsa"; string pattern = @"\(?.+?)\"; Regex rr = new Regex(pattern, RegexOptions.IgnoreCase);
MatchCollection matches = rr.Matches(m); foreach (Match match in matches)
{
linkA = match.Groups["linkA"].Value;
textA = match.Groups["textA"].Value;
}

c#代码,需要using system.text.regularexpressions;

    string linka = string.empty;     string texta = string.empty;

    string m="<a href='dd.asp'>qsa</a>";

    string pattern = @"\<a.*?href='(?<linka>.+?)'.*\>(?<texta>.+?)\</a\>";

    regex rr = new regex(pattern, regexoptions.ignorecase);     matchcollection matches = rr.matches(m);

    foreach (match match in matches)     {     linka = match.groups["linka"].value;     texta = match.groups["texta"].value;     }

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