急需300道因式分解题及其答案！！

急需300道因式分解题及其答案！！

1-1/4x^2=(1-x/2)(1+x/2)4x–2x^2–2=-2(x^2-2x+1)=-2(x-1)^2(x-y)^3–(y-x)=(x-y)[(x-y)^2+1]x^2–y^2–x+y=(x+y)( x-y)-( x-y)=(x-y)(x+y-1)x^2–y^2－1/(x+y)(x–y)= (x^2–y^2)－1/(x^2-y^2)x^2+1/x^2－2－（x－1/x)^2 = (x-1/x）^2－（x-1/x)^2=0a^3－a^2－2a= a(a^2-a-2)= a(a-2) (a+1)4m^2－9n^2－4m+1=(2m-1)^2-9n^2=(2m-1-3n) (2m-1+3n)3a^2+bc－3ac-ab=3a(a-c)-b(a-c)= (a-c)(3a-b)9－x^2+2xy－y^2=9-(x-y)^2=(3-x-y) (3+x-y)2x^2－3x+1=(2x-1)(x-1) 2x^2+5xy+2y^2=(2x+y)(x+2y)10a(x－y)^2－5b(y－x)=[10a（x-y）+5b]（x-y）=（10a x-10a y+5b）（x-y）a^(n+1)－4a^n＋4a^(n-1)= a^(n-1)(a^2－4a＋4)=a^(n-1)(a-2) ^2x^3(2x－y)－2x＋y= x^3(2x－y)－(2x-y)= (2x-y)( x^3-1)= (2x-y)( x-1)(x^2-x+1)x(6x－1)－1=6x^2-x-1=(3x+1)(2x-1)2ax－10ay＋5by-bx=x（2a-b）-y(2a-b)=（x-y）（2a-b）1－a^2－a/b－1/4b^2=1-(a-1/2b)^2=(1-a+1/2b) (1+a-1/2b)a^4＋4=(a^4+2a^3+2a^2)-(2a^3+4a^2+4a)+(2a^2+4a+4)=a^2(a^2+2a+2)-2a(a^2+2a+2)+2(a^2+2a+2) =(a^2+2a+2)(a^2-2a+2)(x^2＋x)(x^2＋x－3)＋2=(x^2＋x)^2-3(x^2＋x)+2=(x^2＋x-2) (x^2＋x-1)=(x＋2) (x-1) (x^2＋x-1)x^5y－9xy^5=xy(x^4-9y^4) =xy(x^2-3y^2) (x^2+3y^2)－4x^2＋3xy＋y^2=（y-x）（y+4x）4a－a^5=a(4- a^4)= a(2- a^2)(2+a^2)2x^2－4x＋1=4x^2-4x＋1-2x^2=(2x-1)^2-2x^2=(2x-1-√2 x) (2x-1+√2 x)4y^2＋4y－5=(2y+1) ^2-6=(2y+1-√6) (2y+1+√6)3X^2－7X+2=(3X-1)(X-2)8xy(x－y)－2(y－x)^3=2(x-y)[4xy+(x-y)^2]= 2(x-y)(x+y)^2x^6－y^6=（x^3-y^3）（x^3+y^3）=（x-y）（x^2+xy+y^2）（x+y）（x^2-xy+y^2）x^3＋2xy－x－xy^2= x[x^2-(y-1) ^2]= x(x+y-1) (x-y+1)(x＋y)(x＋y－1)－12=(x+y)^2-(x+y)-12=(x+y-4) (x+y+3)4ab－（1－a^2）（1－b^2）=4ab-1+ a^2+ b^2-a^2b^2=(a+b)^2-(ab+1)^2=(a+b-ab-1)(a+b+ab+1)－3m^2－2m＋4 用求根法 求出两根为(1±√13）/（-3）原式=[m+(1-√13）/3][m+(1+√13）/3] a^2－a－6=（a-3）（a+2）2(y－z)＋81(z－y)= 79(z－y)9m^2－6m＋2n－n^2=（3m-1）^2-（n-1）^2=（3m-1+ n-1）（3m-1-n+1）ab(c^2＋d^2)＋cd(a^2＋b^2)= abc^2+ abd^2＋cda^2＋cdb^2=bc(ac+db)+ad(bd+ac)=(ac+db)(bc+ad)a^4－3a^2－4=（a^2-4）（a^2+1）=（a^2+1）（a^2+2）（a^2-2）

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