Excel表格 版本：2007忘记了密码怎么办，有什么办法解开！！急急...
答案:4 悬赏:40 手机版
解决时间 2021-02-09 16:24
- 提问者网友：我没有何以琛的痴心不悔
- 2021-02-08 15:34
Excel表格 版本：2007忘记了密码怎么办，有什么办法解开！！急急...
最佳答案
- 五星知识达人网友：佘樂
- 2021-02-08 16:45
Advanced Office Password Recovery 这个软件可以破解。不过需要时间。
全部回答
- 1楼网友：玩家
- 2021-02-08 18:27
如果你的表格里面没有什么重要的东西的话，可以发到我QQ394147166邮箱里面，我帮你破解了再发给你
- 2楼网友：笑迎怀羞
- 2021-02-08 17:38
是保护工作表密码吗？如果是，可以用宏代码进行破解，方法如下
（1）打开工作表
（2）按“alt+f11”调出vba编辑器，选择“插入”—“模块”—把下列“宏代码”粘贴进去保存，退出vba编辑器，回到工作表界面
public sub excel密码破解()
const dblspace as string = vbnewline & vbnewline
const authors as string = dblspace & vbnewline & _
"adapted from bob mccormick base code by" & _
"norman harker and je mcgimpsey"
const header as string = "allinternalpasswords user message"
const version as string = dblspace & "version 1.1.1 2003-apr-04"
const repback as string = dblspace & "please report failure " & _
"to the microsoft.public.excel.programming newsgroup."
const allclear as string = dblspace & "the workbook should " & _
"now be free of all password protection, so make sure you:" & _
dblspace & "save it now!" & dblspace & "and also" & _
dblspace & "backup!, backup!!, backup!!!" & _
dblspace & "also, remember that the password was " & _
"put there for a reason. don't stuff up crucial formulas " & _
"or data." & dblspace & "access and use of some data " & _
"may be an offense. if in doubt, don't."
const msgnopwords1 as string = "there were no passwords on " & _
"sheets, or workbook structure or windows." & authors & version
const msgnopwords2 as string = "there was no protection to " & _
"workbook structure or windows." & dblspace & _
"proceeding to unprotect sheets." & authors & version
const msgtaketime as string = "after pressing ok button this " & _
"will take some time." & dblspace & "amount of time " & _
"depends on how many different passwords, the " & _
"passwords, and your computer's specification." & dblspace & _
"just be patient! make me a coffee!" & authors & version
const msgpwordfound1 as string = "you had a worksheet " & _
"structure or windows password set." & dblspace & _
"the password found was: " & dblspace & "$$" & dblspace & _
"note it down for potential future use in other workbooks by " & _
"the same person who set this password." & dblspace & _
"now to check and clear other passwords." & authors & version
const msgpwordfound2 as string = "you had a worksheet " & _
"password set." & dblspace & "the password found was: " & _
dblspace & "$$" & dblspace & "note it down for potential " & _
"future use in other workbooks by same person who " & _
"set this password." & dblspace & "now to check and clear " & _
"other passwords." & authors & version
const msgonlyone as string = "only structure / windows " & _
"protected with the password that was just found." & _
allclear & authors & version & repback
dim w1 as worksheet, w2 as worksheet
dim i as integer, j as integer, k as integer, l as integer
dim m as integer, n as integer, i1 as integer, i2 as integer
dim i3 as integer, i4 as integer, i5 as integer, i6 as integer
dim pword1 as string
dim shtag as boolean, wintag as boolean
application.screenupdating = false
with activeworkbook
wintag = .protectstructure or .protectwindows
end with
shtag = false
for each w1 in worksheets
shtag = shtag or w1.protectcontents
next w1
if not shtag and not wintag then
msgbox msgnopwords1, vbinformation, header
exit sub
end if
msgbox msgtaketime, vbinformation, header
if not wintag then
msgbox msgnopwords2, vbinformation, header
else
on error resume next
do 'dummy do loop
for i = 65 to 66: for j = 65 to 66: for k = 65 to 66
for l = 65 to 66: for m = 65 to 66: for i1 = 65 to 66
for i2 = 65 to 66: for i3 = 65 to 66: for i4 = 65 to 66
for i5 = 65 to 66: for i6 = 65 to 66: for n = 32 to 126
with activeworkbook
.unprotect chr(i) & chr(j) & chr(k) & _
chr(l) & chr(m) & chr(i1) & chr(i2) & _
chr(i3) & chr(i4) & chr(i5) & chr(i6) & chr(n)
if .protectstructure = false and _
.protectwindows = false then
pword1 = chr(i) & chr(j) & chr(k) & chr(l) & _
chr(m) & chr(i1) & chr(i2) & chr(i3) & _
chr(i4) & chr(i5) & chr(i6) & chr(n)
msgbox application.substitute(msgpwordfound1, _
"$$", pword1), vbinformation, header
exit do 'bypass all for...nexts
end if
end with
next: next: next: next: next: next
next: next: next: next: next: next
loop until true
on error goto 0
end if
if wintag and not shtag then
msgbox msgonlyone, vbinformation, header
exit sub
end if
on error resume next
for each w1 in worksheets
'attempt clearance with pword1
w1.unprotect pword1
next w1
on error goto 0
shtag = false
for each w1 in worksheets
'checks for all clear shtag triggered to 1 if not.
shtag = shtag or w1.protectcontents
next w1
if shtag then
for each w1 in worksheets
with w1
if .protectcontents then
on error resume next
do 'dummy do loop
for i = 65 to 66: for j = 65 to 66: for k = 65 to 66
for l = 65 to 66: for m = 65 to 66: for i1 = 65 to 66
for i2 = 65 to 66: for i3 = 65 to 66: for i4 = 65 to 66
for i5 = 65 to 66: for i6 = 65 to 66: for n = 32 to 126
.unprotect chr(i) & chr(j) & chr(k) & _
chr(l) & chr(m) & chr(i1) & chr(i2) & chr(i3) & _
chr(i4) & chr(i5) & chr(i6) & chr(n)
if not .protectcontents then
pword1 = chr(i) & chr(j) & chr(k) & chr(l) & _
chr(m) & chr(i1) & chr(i2) & chr(i3) & _
chr(i4) & chr(i5) & chr(i6) & chr(n)
msgbox application.substitute(msgpwordfound2, _
"$$", pword1), vbinformation, header
'leverage finding pword by trying on other sheets
for each w2 in worksheets
w2.unprotect pword1
next w2
exit do 'bypass all for...nexts
end if
next: next: next: next: next: next
next: next: next: next: next: next
loop until true
on error goto 0
end if
end with
next w1
end if
msgbox allclear & authors & version & repback, vbinformation, header
end sub
（3）按“alt+f8”调出宏，选择“excel密码破解”，点击“执行”，之后再点击几次“确定”，等宏代码执行完毕，密码就没有了，祝你好运！
- 3楼网友：渊鱼
- 2021-02-08 17:19
下一个密码破解器破解一下就行了，前提是你的密码不是太长。
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