怎样得到shellcode?

怎样得到shellcode ?就是十六进制形式的机器语言

你直接拿去用去吧。不给你解释了

void ShellCodeGenerater(char *file)
{
int iFileSize;
FILE *fp = NULL;

fp = fopen(file, "rb");
if( fp == NULL )
{
printf("Error: Unable to open %s!\n", file);
exit(1);
}
//计算文件大小
fseek(fp, 0, SEEK_END);
iFileSize = ftell(fp);
fseek(fp, 0, SEEK_SET);

BYTE bb;
char *buff = new char[iFileSize+2];
if( fgets(buff, iFileSize+1, fp) == NULL )
{
printf("Error: Unable to read from file.\n");
exit(1);
}

FILE* myfile;
myfile = fopen("ShellCode.txt","w");
// fprintf(myfile,"#include <stdio.h>\n");

fprintf(myfile,"char shellcode[] = \n");
fprintf(myfile, "\"");
for( int i=0 ; i < iFileSize ; i++ )
{
bb = buff[i];

fprintf(myfile,"\\x%2.2X", bb);
if(i%20==0)
{
fprintf(myfile,"\"");
fprintf(myfile,"\n\"");
}

}

fclose(fp);
return;
}

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