#include
int main(void)
{
long sum=0L;
int count=0;
printf("\nEnter the number of intergers you want to sum ：");
scanf("%d",&count);
for (int i=1;i<=count;i++)
sum+=i;
{
printf("\nTotal of the first %d numbers is %ld\n",count,sum);
return 0;
}
C语言for (int i=1;i<=count;i++)编译不通过。
答案:2 悬赏:0 手机版
解决时间 2021-02-25 06:46
- 提问者网友：难遇难求
- 2021-02-25 00:23
教科书上面照打出来的，但是编译不通过。求解。我用的Dev-C++.
#include
int main(void)
{
long sum=0L;
int count=0;
printf("\nEnter the number of intergers you want to sum ：");
scanf("%d",&count);
for (int i=1;i<=count;i++)
sum+=i;
{
printf("\nTotal of the first %d numbers is %ld\n",count,sum);
return 0;
}
#include
int main(void)
{
long sum=0L;
int count=0;
printf("\nEnter the number of intergers you want to sum ：");
scanf("%d",&count);
for (int i=1;i<=count;i++)
sum+=i;
{
printf("\nTotal of the first %d numbers is %ld\n",count,sum);
return 0;
}
最佳答案
- 五星知识达人网友：廢物販賣機
- 2021-02-25 01:37
少了一个括号}，
int main(void)
{
long sum=0L;
int count=0;
printf("\nEnter the number of intergers you want to sum ：");
scanf("%d",&count);
for (int i=1;i<=count;i++)
sum+=i;
{
printf("\nTotal of the first %d numbers is %ld\n",count,sum);
return 0;
}
}
int main(void)
{
long sum=0L;
int count=0;
printf("\nEnter the number of intergers you want to sum ：");
scanf("%d",&count);
for (int i=1;i<=count;i++)
sum+=i;
{
printf("\nTotal of the first %d numbers is %ld\n",count,sum);
return 0;
}
}
全部回答
- 1楼网友：鸽屿
- 2021-02-25 01:52
如果你用的是c的编译器(不是c++的)，那么是不允许在for的()中声明变量类型的。把i在前面声明，()中只写i=1就行了……
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