展开并化简下列各式(a-2b+c)(a+2b-c)-(a+2b+c)2(x+y)2(x-y)2(a+b)(a-b)(a2+2ab+b2)(a2-
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解决时间 2021-03-24 06:20
- 提问者网友:精神病院里
- 2021-03-23 06:03
展开并化简下列各式(a-2b+c)(a+2b-c)-(a+2b+c)2(x+y)2(x-y)2(a+b)(a-b)(a2+2ab+b2)(a2-
最佳答案
- 五星知识达人网友:怙棘
- 2021-03-23 07:21
(1)原式=[a-(2b-c)][(a+(2b-c)]-(a+2b+c)2
=a2-(2b-c)2-(a+2b+c)2
=a2-(4b2-4bc+c2)-(a2+4b2+c2+4ab+2ac+4bc)
=a2-4b2+4bc-c2-a2-4b2-c2-4ab-2ac-4bc
=-4b2-c2-4b2-c2-4ab-2ac
=-8b2-2c2-4ab-2ac;
(2)原式=[(x+y)(x-y)]2
=(x2-y2)2
=x4-2x2y2+y4;
(3)原式=(a+b)(a-b)(a+b)2(a-b)2
=(a+b)3(a-b)3
=[(a+b)(a-b)]3
=(a2-b2)3
=(a4-2a2b2+b4)(a2-b2)
=a6-3a4b2+3a2b4-b6;
(4)原式=[(m-2c)+(2x+z)][(m-2c)-(2x+z)]
=(m-2c)2-(2x+z)2
=(m2-4mc+4c2)-(4x2+4xz+z2)
=m2-4mc+4c2-4x2-4xz-z2.
=a2-(2b-c)2-(a+2b+c)2
=a2-(4b2-4bc+c2)-(a2+4b2+c2+4ab+2ac+4bc)
=a2-4b2+4bc-c2-a2-4b2-c2-4ab-2ac-4bc
=-4b2-c2-4b2-c2-4ab-2ac
=-8b2-2c2-4ab-2ac;
(2)原式=[(x+y)(x-y)]2
=(x2-y2)2
=x4-2x2y2+y4;
(3)原式=(a+b)(a-b)(a+b)2(a-b)2
=(a+b)3(a-b)3
=[(a+b)(a-b)]3
=(a2-b2)3
=(a4-2a2b2+b4)(a2-b2)
=a6-3a4b2+3a2b4-b6;
(4)原式=[(m-2c)+(2x+z)][(m-2c)-(2x+z)]
=(m-2c)2-(2x+z)2
=(m2-4mc+4c2)-(4x2+4xz+z2)
=m2-4mc+4c2-4x2-4xz-z2.
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