计算(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)*(2^32+1)+1

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解决时间 2021-02-16 12:02

提问者网友：欲劫无渡
2021-02-15 15:06

计算(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1

最佳答案

五星知识达人网友：痴妹与他
2021-02-15 16:27

(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2^2-1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2^4-1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2^8-1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2^16-1)*(2^16+1)*(2^32+1)+1
=(2^32-1)*(2^32+1)+1
=2^64-1+1
=2^64

全部回答

1楼网友：胯下狙击手
2021-02-15 20:45

=(2^2-1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=2^23

2楼网友：我住北渡口
2021-02-15 20:09

(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2-1)(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2^2-1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=2^64-1+1=2^64

3楼网友：轻雾山林
2021-02-15 18:46

(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2-1)(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2^2-1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=2^64-1+1=2^64

4楼网友：天凉才是好个秋
2021-02-15 18:05

(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2-1)(2+1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=(2^2-1)*(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)+1
=2^64-1+1=2^64

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