1+1/2+1/3-1/4+........+1/49-1/50这整道算式再除以
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解决时间 2021-01-06 08:14
- 提问者网友：沉默的哀伤
- 2021-01-06 02:17
1+1/2+1/3-1/4+........+1/49-1/50这整道算式再除以
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- 五星知识达人网友：愁杀梦里人
- 2021-01-06 02:27
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- 1楼网友：雪起风沙痕
- 2021-01-06 03:04
1-1/2+1/3-1/4......+1/49-1/50
=1-1/2+1/3-1/4......+1/49-1/50+(1/2+1/4+1/6+......+1/50)-(1/2+1/4+1/6+......+1/50)
=1+1/2+1/3+1/4......+1/49+1/50-2*(1/2+1/4+1/6+......+1/50)
=1+1/2+1/3+1/4......+1/49+1/50-(1+1/2+1/3+......+1/25)
=1/26+1/27+......+1/49+1/50
1/52+1/54+.......1/100
=1/2*26+1/2*27+.......1/2*50
=1/2*(=1/26+1/27+......+1/49+1/50)
(1-1/2+1/3-1/4+…+1/49-1/50)÷(1/(51+1)+1/(52+2)+…+1/(75+25))
=(1/26+1/27+......+1/49+1/50)÷(1/2*(1/26+1/27+…+1/50))
=2
=1-1/2+1/3-1/4......+1/49-1/50+(1/2+1/4+1/6+......+1/50)-(1/2+1/4+1/6+......+1/50)
=1+1/2+1/3+1/4......+1/49+1/50-2*(1/2+1/4+1/6+......+1/50)
=1+1/2+1/3+1/4......+1/49+1/50-(1+1/2+1/3+......+1/25)
=1/26+1/27+......+1/49+1/50
1/52+1/54+.......1/100
=1/2*26+1/2*27+.......1/2*50
=1/2*(=1/26+1/27+......+1/49+1/50)
(1-1/2+1/3-1/4+…+1/49-1/50)÷(1/(51+1)+1/(52+2)+…+1/(75+25))
=(1/26+1/27+......+1/49+1/50)÷(1/2*(1/26+1/27+…+1/50))
=2
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