分式加减 .化简求值 (x-y分之1

分式加减 .
化简求值 (x-y分之1 - x+y分之1)÷x平方-2xy+y平方分之2y

[1/(x-y) - 1/(x+y)]÷2y/(x^2-2xy+y^2)
=[(x+y)/(x+y)(x-y) - (x-y)/(x+y)(x-y)]÷2y/(x-y)^2
=[(x+y - x+y)/(x+y)(x-y)]÷2y/(x-y)^2
=[2y/(x+y)(x-y)]÷2y/(x-y)^2
=2y/(x+y)(x-y)*(x-y)^2/2y
=(x-y)/(x+y)

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