求高手帮合并下c程序

#include
#include
int main(void)
{
uint16_t count;
uint16_t timeLeft,timeRight;
usta_Init();
while(1)
{
DDRC|=_BV(PC0);
PORTC|=_BV(PC0);
delay_nms(2);
TCNT1=0;
DDRC&=~_BV(PC0);
TCCR1B=_BV(CS10);
while((PINC&0x01)!=0);
count=TCNT1;
timeLeft=count/4;
DDRC|=_BV(PC1);
PORTC|=_BV(PC1);
delay_nms(2);
TCNT1=0;
DDRC&=~_BV(PC1);
TCCR1B=_BV(CS10);
while((PINC&0x02)!=0);
count=TCNT1;
timeRight=count/4;
printf("timeLeft = %u us ",timeLeft);
printf("timeRight = %u us\n",timeRight);
delay_nms(100);
}
}
另
#include
#include
int PC0_state(void)
{
return (PINC&0x01)?1:0;
}
int main(void)
{
usta_Init();
printf("Program Running!");
DDRD|=_BV(PD7);
DDRC|=_BV(PC2)|_BV(PC3);
for(uint16_t counter=1;counter<=600;counter++)//开始/复位信号
{
PORTD|=_BV(PD7);
delay_nus(166);
PORTD&=~_BV(PD7);
delay_nus(166);
}
while(1)
{

if(PC0_state()==0)
{
PORTD|=_BV(PD7);
delay_nus(1000);
PORTD&=~_BV(PD7);
delay_nus(1000);
}

}
}

#include
//可去掉#include
using namespace std;
typedef int datatype;
#define maxsize 1024

typedef struct
{
datatype data[maxsize];
int last;
}sequenlist;

sequenlist *combine (sequenlist *scrptr,sequenlist *sinkptr);//添加函数声明

void main ()
{
sequenlist *Aptr,*Bptr,*Cptr;
Aptr = new sequenlist;//注意，要申请空间，初始化指针，下同
Bptr = new sequenlist;
Cptr = NULL;
//Cptr不用申请空间，因为后面有返回指针，这里初始为NULL，以防非法操作
char ch; //注意这里
int i=0;

//注意这里
do
{
ch = getchar();
Aptr->data[i]= ch - '0';//*Aptr.data[i]——>Aptr->data[i]
i++;
}
while (ch!='\n' && i Aptr->last = i-1; //添加这句

i = 0;

do
{
ch = getchar();
Bptr->data[i]= ch - '0';//*Aptr.data[i]——>Aptr->data[i]
i++;
}
while (ch!='\n' && i Bptr->last = i-1;

Cptr=combine(Aptr,Bptr);//注意这里

for(i=0;ilast;i++)//注意
printf("%d",Cptr->data[i]);

delete Aptr;//前面new的，现在要delete，否则内存泄漏（虽然编译可通过）
delete Bptr;
Aptr = Bptr = Cptr = NULL;//这句可要可不要，只是一个习惯，即delete掉的指针要置空，以防非法操作。
}
void insertlist (sequenlist *lstptr,int x)//istpter——>lstptr
{
int i=0,j=0;

//没有do....until ();应用while
while(ilast)
{
if (x<=lstptr->data[i])
break;
else i++;
}
if (lstptr->last>=maxsize)
{
printf ("overflow");
exit(0);//exit (overflow);overflow不是一个整数值
}
for (j=lstptr->last-1;j>=i;j--)//注意，j=lstptr->last-1
{
lstptr->data[j+1]=lstptr->data[j];
// lstptr->data[i]=x;
// lstptr->last++;
//这两句要放for外面
}
lstptr->data[i]=x;
lstptr->last++;
}

sequenlist *combine (sequenlist *scrptr,sequenlist *sinkptr)
{
//int x;不需要
int j;
for (j=0;jlast;j++)
insertlist (scrptr,sinkptr->data[j]);
return scrptr;//注意
}

如果2个程序没关联，好合并 #include #include int main1(void) { uint16_t count; uint16_t timeLeft,timeRight; usta_Init(); while(1) { DDRC|=_BV(PC0); PORTC|=_BV(PC0); delay_nms(2); TCNT1=0; DDRC&=~_BV(PC0); TCCR1B=_BV(CS10); while((PINC&0x01)!=0); count=TCNT1; timeLeft=count/4; DDRC|=_BV(PC1); PORTC|=_BV(PC1); delay_nms(2); TCNT1=0; DDRC&=~_BV(PC1); TCCR1B=_BV(CS10); while((PINC&0x02)!=0); count=TCNT1; timeRight=count/4; printf("timeLeft = %u us ",timeLeft); printf("timeRight = %u us\n",timeRight); delay_nms(100); } return 0; } int PC0_state(void) { return (PINC&0x01)?1:0; } int main2(void) { usta_Init(); printf("Program Running!"); DDRD|=_BV(PD7); DDRC|=_BV(PC2)|_BV(PC3); for(uint16_t counter=1;counter<=600;counter++)//开始/复位信号 { PORTD|=_BV(PD7); delay_nus(166); PORTD&=~_BV(PD7); delay_nus(166); } while(1) { if(PC0_state()==0) { PORTD|=_BV(PD7); delay_nus(1000); PORTD&=~_BV(PD7); delay_nus(1000); } } return 0; } int main(void) { int i; do { printf("\r\n\r\n"); printf("1 操作功能1\r\n"); printf("2 操作功能2\r\n"); printf("0 退出\r\n"); printf("Please select operate:"); scanf("%d",&i); if(i==1) { main1(); } else if(i==2) { main2(); } else if(i==0) { return 0; } } return 0; } 否则就不会了

楼主是用秦志强的那本书吧，我在做书上的实验时，出现错误如下，有没有哪位大神指导一下 主程序： #include #include int main(void) { usta_Init(); printf("Hello,this is a message from your Robot."); } 头文件usta.h如下： #include #include #include #include char g_aString[81]; int usart_putchar(char c) { if(c=='\n') usart_putchar('\r'); loop_until_bit_is_set(UCSRA,UDRE); UDR=c; return 0; } int usart_getchar(void) { loop_until_bit_is_set(UCSRA,RXC); return UDR; } void usta_Init(void) { UCSRB=_BV(RXEN)|_BV(TXEN); UBRRL=25; fdevopen(usart_putchar,usart_getchar,0); } MAKE ALL 后 avr-gcc (GCC) 3.4.3 Copyright (C) 2004 Free Software Foundation, Inc. This is free software; see the source for copying conditions. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. Compiling: HelloRobot.c avr-gcc -c -mmcu=atmega128 -I. -gdwarf-2 -DF_CPU=8000000UL -Os -funsigned-char -funsigned-bitfields -fpack-struct -fshort-enums -Wall -Wstrict-prototypes -Wa,-adhlns=HelloRobot.lst -std=gnu99 -MD -MP -MF .dep/HelloRobot.o.d HelloRobot.c -o HelloRobot.o In file included from HelloRobot.c:2: D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h: In function `usart_putchar': D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h:10: error: `UCSRA' undeclared (first use in this function) D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h:10: error: (Each undeclared identifier is reported only once D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h:10: error: for each function it appears in.) D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h:11: error: `UDR' undeclared (first use in this function) D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h: In function `usart_getchar': D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h:16: error: `UCSRA' undeclared (first use in this function) D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h:17: error: `UDR' undeclared (first use in this function) D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h: In function `usta_Init': D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h:21: error: `UCSRB' undeclared (first use in this function) D:/SOFTWARE/winavr/bin/../lib/gcc/avr/3.4.3/../../../../avr/include/avr/usta.h:22: error: `UBRRL' undeclared (first use in this function) HelloRobot.c:7:4: warning: no newline at end of file make.exe: *** [HelloRobot.o] Error 1 > Process Exit Code: 2

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