永发信息网

【分式约分和通分(1),(2),是约分(3),(4)是通分通分要写出最简公分母,】

答案:2  悬赏:10  手机版
解决时间 2021-02-22 21:13
  • 提问者网友:记得曾经
  • 2021-02-22 04:23
【分式约分和通分(1),(2),是约分(3),(4)是通分通分要写出最简公分母,】
最佳答案
  • 五星知识达人网友:拾荒鲤
  • 2021-02-22 04:32
1:原式=a(a-b)/(a+b)(a-b)=a/(a+b)2:原式=(3a+2b)(3a-2b)/(3a-2b)^2=(3a+2b)/(3a-2b)3:左式=5/(x+1)(x-1),右式=x/(x-1)^2,两式通分左式=5(x-1)/(x^3-x^2-x+1),右式=(x^2+x)/(x^3-x^2-x+1)4:通分左式=2xy(x-y)/(x+y)^2(x-y)=(2x^2y-2xy^2)/(x^3+x^2y-xy^2-y^3)右式=x(x+y)/(x+y)(x^2-y^2)=(x^2+xy)/(x^3+x^2y-xy^2-y^3)======以下答案可供参考======供参考答案1:(1)分子=a(a-b) 分母=(a+b)(a-b)a-b不等于零,否则不可为分母,约a-b得a-----a+b供参考答案2:(1)原式=a(a-b)/[(a-b)(a+b)]=a/(a+b)(2)原式=(3a-2b)(3a+2b)/(3a-2b)^2=(3a+2b)/(3a-2b)(3)原式=5/[(x-1)(x+1)] 和x/(x-1)^2 最简分母:[(x-1)^2(x+1)]所以5(x-1)/[(x-1)^2(x+1)]和x(x+1)/[(x-1)^2(x+1)](4)原式=2xy(x-y)/[(x+y)^2(x-y)]和x(x+y)/[(x+y)^2(x-y)] 最简分母:[(x+y)^2(x-y)]供参考答案3:(1)(a^2-ab)/(a^2-b^2)=a(a-b)/(a+b)(a-b)=a/(a+b)(2)(9a^2-4b^2)/(9a^2-12ab+4b^2)=(3a+2b)(3a-2b)/(3a-2b)^2=(3a+2b)/(3a-2b)(3)5/(x^2-1)=5/(x+1)(x-1)=5(x-1)/(x+1)(x-1)^2x/(x^2-2x+1)=x/(x-1)^2=x(x+1)/(x+1)(x-1)^2(4)2xy/(x+y)^2=2xy(x-y)/(x-y)(x+y)^2
全部回答
  • 1楼网友:佘樂
  • 2021-02-22 06:08
我学会了
我要举报
如以上回答内容为低俗、色情、不良、暴力、侵权、涉及违法等信息,可以点下面链接进行举报!
点此我要举报以上问答信息
大家都在看
推荐资讯